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aev [14]
1 year ago
13

How many distinct 9-letter words starting with “i” can be formed from the word “committee”?

Mathematics
1 answer:
Nikitich [7]1 year ago
7 0

We have already chosen "i" to be the first letter. This means that we still have 8 letters that we can use as the second letter. Once that letter is chosen, we still have 7 letters that we can use as the third letter, and so on. This means we have

8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 8!

ways of choosing the remaining 8 letters.

<u>However,</u> some of the 8 available letters are equal: we have 2 m's, 2 t's and 2 e's. This means that we overcounted the number of words on the reasoning above. We can correct the counting by dividing three times by 2!, one time for each of the repeated letters.

The final answer is

\dfrac{8!}{2! \times 2! \times 2!} = \dfrac{40320}{8} = 5040.

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A spinner is divided into 8 equal sections. lara spins the spinner 120 times. it lands on purple 30 times. how many more times d
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She should not spin the spinner any more times, the relative probability is already more than the theoretical probability.

If there is only 1 purple section out of 8, that gives purple a 12.5% chance of being spun.

However, Lara got purple 30 out of 120 times. That is 25%. She is already over.

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Write the ratio as a fraction in simplest form: 2.35 to 5.25.
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Step-by-step explanation:

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4 0
1 year ago
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Liam says - G) is equivalent to Explain if Liam is correct by completing the
vredina [299]

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8 0
1 year ago
An experienced carpenter can frame a house twice as fast as an apprentice. Working together, it takes the carpenters 2 days. How
AleksAgata [21]

Answer:

<em>6 days</em>

<em></em>

Step-by-step explanation:

Let the time taken by Carpenter working alone = C days

Then time taken by apprentice alone = Twice as that of taken by Carpenter = 2C days

Time taken working together = 2 days

Work done in one day working together = \frac{1}{2}

Work done in one day by Carpenter working alone = \frac{1}{C}

Work done in one day by apprentice working alone = \frac{1}{2C}

Work done in one day by Carpenter working alone + Work done in one day by Carpenter working alone =  \frac{1}{C}+\frac{1}{2C} = Work done in one day working together = \frac{1}{2}

\dfrac{1}{C}+\dfrac{1}{2C}=\dfrac{1}{2}\\\Rightarrow \dfrac{2+1}{2C}=\dfrac{1}{2}\\\Rightarrow C = 3\ days

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Time taken by Apprentice alone to complete the work = 3 \times 2= <em>6 days</em>

4 0
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