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OLga [1]
2 years ago
6

Which graph shows the solution set of the compound inequality 1.5 x minus 1 greater-than 6.5 or 7 x + 3 less-than negative 25?

Mathematics
2 answers:
saul85 [17]2 years ago
5 0

Answer:

After solving the compound inequality 1.5x-1>6.5 \ or \ 7x+3 we get \mathbf{x>5 \ or \ x

Option B is correct.

Step-by-step explanation:

We are given compound inequality: 1.5x-1>6.5 \ or \ 7x+3

We will first solve the inequalities to find the value of x, then will draw the graph.

1.5x-1>6.5 \ or \ 7x+36.5+1 \ or \ 7x+3-37.5 \ or \ 7x\frac{7.5}{1.5} \ or \ x5 \ or \ x< -4

So, after solving the compound inequality 1.5x-1>6.5 \ or \ 7x+3 we get \mathbf{x>5 \ or \ x

Now, the number line will be as shown in figure.

The description as given in options is:

A number line goes from negative 10 to positive 10. An open circle appears at negative 4 and positive 5. The number line is shaded from negative 4 toward negative 10. The number line is also shaded from positive 5 toward positive 10.

so, Option B is correct.

Karo-lina-s [1.5K]2 years ago
4 0

Answer:

the answer is b

Step-by-step explanation:

2020 edge

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La fuerza necesaria para evitar que un auto derrape en una curva varía inversamente al radio de la curva y conjuntamente con el
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Answer:

768 libras de fuerza

Step-by-step explanation:

Tenemos que encontrar la ecuación que los relacione.

F = Fuerza necesaria para evitar que el automóvil patine

r = radio de la curva

w = peso del coche

s = velocidad de los coches

En la pregunta se nos dice:

La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.

F ∝ 1 / r

Y luego con el peso del auto

F ∝ w

Y el cuadrado de la velocidad del coche

F ∝ s²

Combinando las tres variaciones juntas,

F ∝ 1 / r ∝ w ∝ s²

k = constante de proporcionalidad, por tanto:

F = k × w × s² / r

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Paso 1

Encuentra k

En la pregunta, se nos dice:

Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.

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Tenga en cuenta que desde el

F = kws² / r

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Paso 2

¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?

F = ?? libras

w = ya que es el mismo carro = 1600 libras

r = 600

s = 60 mph

F = kws² / r

k = 2/25

F = 2/25 × 1600 × 60² / 600

F = 768 libras

Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.

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Step-by-step explanation:

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Lots of love and peace your way!!  <3

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