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posledela
2 years ago
12

What is the approximate value of b, rounded to the nearest tenth? Use the law of sines to find the answer. Triangle A B C is sho

wn. Angle C A B is 66 degrees and angle A B C is 76 degrees. The length of A B is 3 and the length of A C is b. Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction 1.9 units 4.7 units 5.0 units 5.7 units
Mathematics
2 answers:
Brilliant_brown [7]2 years ago
6 0

Answer:

4.7 units

Step-by-step explanation:

Setler79 [48]2 years ago
5 0

Answer:

4.7 units

Step-by-step explanation:

We are given that in triangle ABC

AB= 3 units

Angle ABC=76 degree

Angle CAB=66 degrees

AC=b

We have to find the approximate value of b using sin laws.

We know that sum of angles of a triangle =180 degrees

\angle CAB+\angle ABC+\angle ACB=180

76+66+\angle ACB=180

142+\angle ACB=180

\angle ACB=180-142=38^{\circ}

We know that law of sines

\frac{BC}{Sin A}=\frac{AC}{SinB}=\frac{AB}{sin C}

Substitute the values then we get

\frac{b}{sin 76^{\circ}}=\frac{3}{sin 38^{\circ}}

b=\frac{3}{sin 38^{\circ}}\times sin 76^{\circ}

b=4.7

Hence, the value of b= 4.7 units

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