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Alex Ar [27]
2 years ago
13

A culture of 1.08×1015 bacteria is in petri dish A. A culture of 2.7×1011 bacteria is in petri dish B. How many times greater is

the number of bacteria in petri dish A than petri dish B? Enter your answer, in standard notation, in the box
Mathematics
2 answers:
charle [14.2K]2 years ago
6 0

Answer:

4,000 times greater 4*10^3

Step-by-step explanation:

xxTIMURxx [149]2 years ago
4 0
<span>Culture in petri dish A is 1.08 x 10^15 and culture in petri dish B is 2.7 X 10^11. To determine how much greater petri dish A is from petri dish b, you must divide petri dish A by petri dish b. When you divide the two numbers, the answer is 4,000. The number of bacteria in petri dish A is four thousand times greater than the number of bacteria in petri dish B.</span>
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Part A: During what interval(s) of the domain is the water balloon's height increasing?
Advocard [28]

Answer:

The answer is below

Step-by-step explanation:

The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds: A linear model with ordered pairs at 0, 60 and 2, 75 and 4, 75 and 6, 40 and 8, 20 and 10, 0 and 12, 0 and 14, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet. Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(s) of the domain is the water balloon's height staying the same? (2 points) Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points) Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds.

Answer:

Part A: During what interval(s) of the domain is the water balloon's height increasing?

Between 0 and 2 seconds, the height of the balloon increases from 60 feet to 75 feet

Part B: During what interval(s) of the domain is the water balloon's height staying the same?

Between 2 and 4 seconds, the height remains the same at 75 feet. Also from 10 seconds the height of the balloon is at 0 feet

Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest?

Between 4 and 6 seconds, the height of the balloon decreases from 75 feet to 40 feet (i.e. -17.5 ft/s)

Between 6 and 8 seconds, the height of the balloon decreases from 40 feet to 20 feet (i.e. -10 ft/s)

Between 8 and 10 seconds, the height of the balloon decreases from 20 feet to 0 feet (i.e. -10 ft/s)

Hence it decreases fastest from 4 to 6 seconds

Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds

From 10 seconds, the balloon is at the ground, so it remains at the ground (0 feet) even at 16 seconds

6 0
2 years ago
The cost, c(x), for a taxi ride is given by c(x) = 3x + 2.00, where x is the number of minutes. What does the slope mean for thi
xxTIMURxx [149]
Simple...

you have: C(X)=3x+2.00

x=number of minutes

Pay attention to the y=mx+b form where m=slope-->>

3x is the slope...

so it's 3(times the number of minutes) <<---or (x)

This means that the slope is 3, or the fancy way of saying it-->>"rate of change."

The rate of change of the cost of the taxi ride is $3.00 per minute.

Thus, your answer.


7 0
2 years ago
Hank bought 3 more boxes of cereal than gallons of milk. He bought x boxes of cereal at $2.79 each. Each
Over [174]

Answer:

true

Step-by-step explanation:

8 0
2 years ago
Two students from a group of eight boys and 12 girls are sent to represent the school in a parade. If the students are chosen at
kari74 [83]

Answer:

Step-by-step explanation:

* Lets explain how to find the probability of an event  

- The probability of an Event = Number of favorable outcomes ÷ Total

 number of possible outcomes

- P(A) = n(E) ÷ n(S) , where

# P(A) means finding the probability of an event A  

# n(E) means the number of favorable outcomes of an event

# n(S) means set of all possible outcomes of an event

- Probability of event not happened = 1 - P(A)

- P(A and B) = P(A) . P(B)

* Lets solve the problem

- There is a group of students

- There are 8 boys and 12 girls in the group

∴ There are 8 + 12 = 20 students in the group

- The students are sent to represent the school in a parade

- Two students are chosen at random

∴ P(S) = 20

- The students that chosen are not both girls

∴ The probability of not girls = 1 - P(girls)

∵ The were 20 students in the group

∵ The number of girls in the group was 12

∴ The probability of chosen a first girl = 12/20

∵ One girl was chosen, then the number of girls for the second

  choice is less by 1 and the total also less by 1

∴ The were 19 students in the group

∵ The number of girls in the group was 11

∴ The probability of chosen a second girl = 11/19

- The probability of both girls is P(1st girle) . P(2nd girl)

∴ The probability of both girls = (12/20) × (11/19) = 33/95

- To find the probability of both not girls is 1 - P(both girls)

∴ P(not both girls) = 1 - (33/95) = 62/95

* The probability that the students chosen are not both girls is 62/95

3 0
2 years ago
Read 2 more answers
A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a random
Harlamova29_29 [7]

Answer with explanation:

Given : Sample mean =\overline{x}=\text{48.47 pounds}

Standard deviation : \sigma=\text{ 3.1 pounds.}

Sample size : n = 36

Claim : \mu\neq50

∴ H_0:\mu=50

H_1:\mu\neq50

Since the alternative hypothesis is two tail , then the test is two tail test.

By using a z statistic and a 0.05 level of significance. Reject  H_0 if z < -1.960 or is z> 1.960.

Then , the test static for population mean is given by :-

z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

z=\dfrac{48.47-50}{\dfrac{3.1}{\sqrt{36}}}\approx-2.96

We reject H_0 since -2.96\leq -1.96. We have statistically significant evidence at \alpha=0.05 to show that the mean amount of garbage per bin is not different from 50.  

5 0
2 years ago
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