Answer: The correct option is tan(F).
Explanation:
In the given figure the triangle is a right angle triangle because 
.
It is also given that 
and 
.
Since it is an isosceles right angle triangle, therefore the value of perpendicular and base is same for both angles D and F, which is 5.
The value of cos(F) is 
.
The value of sin(F) is .
The value of sin(D) is .
The value of tan(F) is 1. Which is not equal to .
The value of cos(D) is .
Therefore, the value of tan(F) is not equal to the value of cos(F), so the correct option is third.
There are a couple of ways you can solve this. You can write it out like
(K-3)(K-3)(K-3)(K-3)(K-3)(K-3)(K-3)
And pretty much use the foil method
Or you can use the binomial theorem (google it if you dont know)
The solution should be:
(K^7) - 21(k^6) + 189(k^5) - 945(k^4) + 2835(k^3) - 5103(k^2) + 5103k - 2187
To answer the question, all the statements must be analyzed with the data presented in the table.
From the table we get that the team played 16 games at home and 11 games away from home.
In total, they played 27 games.
Of the 16 games at home, the team won 6. Then, the proportion of games won at home is:
6/16 = 0.375.
Of the 11 games away from home, the team won 3. Then the proportion of games won away from home is:
3/11 = 0.272.
0.375 is not twice 0.272.
Then the first statement is incorrect.
The ratio of games won at home is 6/16 = 3/8. Therefore, the second statement is incorrect. The team does not win 3/5 of the games at home.
The total number of games won is 9 and the total number of games is 27.
So, the third statement is incorrect. The team does not win half of the games.
The fourth statement is true. The team played 27 games
The fifth statement is false because the team won more than 6 games. They won 3 games away from home and 6 games at home
Finally, the sixth statement is correct, because the team lost 10 games at home and 8 away from home. However, the PERCENTAGE of games lost away from home is greater than the PERCENTAGE of games lost at home. Therefore, it is more likely that the team loses when playing away from home.
Answer:
Step-by-step explanation:
Sarah is falling for Pitfalls 5 and 6.
A statistical association does not mean causation. there must be proof to support the cause and effect and even if there were proof to support the cause and effect, extending the result about groups to an individual is not proper
