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dem82 [27]
2 years ago
5

Morgan babysits every saturday. The equation d=9.5h represents how much she earns after h hours. Last week, she also babysat on

friday and earned $63 for 6 hours. Which statement is true?
Mathematics
2 answers:
Pachacha [2.7K]2 years ago
7 0

You would divide the number 63 and 9.5


Then you would get 10.5

So Its 10.5 on friday and 9.5 on saturday



hope this helps:D

DIA [1.3K]2 years ago
3 0

Answer:

morgan earns more money per hour on friday

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A 16-inch candle is lit and burns at a constant rate of 0.8 inches per hour. Let t represent the number of hours since the candl
Tamiku [17]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

a.

The initial length of the candle is 16 inch. It also given that, it burns with a constant rate of 0.8 inch per hour.

After one hour since the candle was lit, the length of the candle will be (16 - 0.8) = 15.2 inch.

After two hour since the candle was lit, the length of the candle will be (15.2 - 0.8) = 14.4 inch. The length of the candle after two hours can also be represented by {16 - 2(0.8)}.

Hence, the length of the candle after t hours when it was lit can be represented by the function, f(t) = 16 - 0.8t. f(t) = 0 at t = 20.

b.

The domain of the function is 0 to 20.

c.

The range is 0 to 16.

8 0
2 years ago
Miss Croft made snack bags for the picnic that contain three types of snacks: packages of crackers, packages of cookies, and can
jek_recluse [69]

Answer: $1.25

Step-by-step explanation:

Let the cost of cracker be a.

Let the cost of cookies be b.

Let the cost of candy bars be c.

From the question,

6a + 6b + 6c = $21

8a + 5b + 10c = $26

5a + 4b + 7c = $18.50

To solve this, we first pick any two pairs of equation. This will be:

6a + 6b + 6c = $21 ....... i

8a + 5b + 10c = $26 ....... ii

Multiply equation i by 8

Multiply equation ii by 6

48a + 48b + 48c = $168 ....... iii

48a + 30b + 60c = $156 ....... iv

Subtract equation iv from iii

18b - 12c = 12

We then pick another two pairs

8a + 5b + 10c = $26

5a + 4b + 7c = $18.50

Multiply equation i by 5

Multiply equation ii by 8

40a + 25b + 50c = $130

40a + 32b + 56c = $148

Subtract the equations

-7b - 6c = -18

Then, solve the new equations formed

18b - 12c = 12 ....... v

-7b - 6c = -18 ....... vi

Multiply equation i by -7

Multiply equation ii by 18

-126b + 84c = -84

-126b - 108c = -324

Subtract the equations

192c = 240

c = 240/129

c = $1.25

From equation v, put the value of c

18b - 12c = 12

18b - 12($1.25) = 12

18b - $15 = $12

18b = $27

b = $27/18

b = $1.5

Since,

6a + 6b + 6c = $21

6a + 6($1.5) + 6($1.25) = $21

6a + $9 + $7.5 = $21

6a + $16.5 = $21

6a = $21 - $16.5

6a = $4.5

a = $4.5/6

a = $0.75

One candy bar cost $1.25

6 0
2 years ago
The volume of an object that is 23 ft wide, 10 ft deep, and 8 ft height is:
monitta
The answer is 1840 because you have to do 10x8 then multiply that by 23 and get 1840
6 0
2 years ago
Read 2 more answers
a person on a tour has rupees 12000 for his daily expenses. In order to extend his journey for 2 more days he had to cut down hi
myrzilka [38]

Answer:

Duration of the tour he planned first is 8 days.

Step-by-step explanation:

Given that a person has 12000 rupees for his daily expenses.

Let x be the number of days.

Then daily expenses per day =\frac{12000}{x}

Given that number of day is increased by 2 more days, that is number of days is x+2.

New daily expense per day \frac{12000}{x+2}

Given that this new daily expenses are 300 less than original.

That is \frac{12000}{x}-\frac{12000}{x+2}=300

              \frac{12000(x+2)-12000x}{x(x+2)}=300

                  \frac{24000}{x(x+2)}=300

                  x(x+2)=\frac{24000}{300}

                    x^{2}+2x-80=0

                    (x-8)(x+10)=0

                     x=8 or -10.

Since number of days cannot be negative, duration of the tour planned=8.

7 0
2 years ago
2.8, 3.4, 4.0, 4.6, . . . Write an equation for the nth term of the arithmetic sequence. Then find a50.
vova2212 [387]

Answer:

a_n = 2.2 + 0.6 n

a_50 = 32.2

Step-by-step explanation:

What's the common difference of this series?

a_1 = 2.8

a_2 = 3.4

Common difference = a_2 - a_1 = 3.4 - 2.8 = 0.6.

Expression for the nth term:

a_n = a_1 + (n - 1) \cdot\text{Common Difference} \\\phantom{a_n } = 2.8 + 0.6 \; (n-1) \\\phantom{a_n} = 2.8 + 0.6 \; n - 0.6\\\phantom{a_n} = 2.2 + 0.6\; n

n = 50 for the fiftieth term. Therefore

a_{50} = 2.2 + 0.6 \times 50 = 32.2.

6 0
2 years ago
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