On top: (-2)³ = -2 × -2 × -2 = -8
(x²)³ = x^6 (the exponents multiply)
and of course, (y)³ = y³
On the bottom: (xy²z)² = x² y^4 z²
(-yz)² = y²z²
Multiplying these together, the exponents add and we get x² y^6 z^4.
So, your reasoning is correct for what you have so far.
Your next step would be cancelling shared factors from the top and bottom.
Just like with regular fractions, if the numerator and denominator are divisible by the same number, you can divide them by it to simplify. (ex: 4/6 = 2/3)
Well, x^6 and x^2 are both divisible by x^2, right?
We can also cancel the y^3.
It might help to visualise the factors like this:
Once you've cancelled out x² and y³ from each, you're left with
Solve for x:
4x-9 >= -21
Add 9 to both sides:
4x >= -12
Divide both sides by 4:
X >= -3
The number line would have a solid dot on -3 with a line and arrow pointing to the right of -3
Answer:
c.) neither
Step-by-step explanation:
-2y = -3/5 does not have an x value for a slope to contrast with y = 4x + 5/3
The difference in tallying of expenses from a day to day and month to month is the consistency. in a day to day basis it is consistent the time for a day is 24 hrs it will not change, so you will really know why the expenses goes up or down/ unlike for a month to month it is inconsistent,, some months have 30, 31 or 28 days in a month.
Here we are given with a triangle with smaller triangles formed due to the altitude on AC. Given:
- AB = 6
- BC = 8
- <ABC = 90°
- BD ⊥ AC
- <ABD =
We have to find the value for sin
So, Let's start solving....
In ∆ADB and ∆ABC,
- <A = <A (common)
- <ABC = <ADB (90°)
So, ∆ADB ~ ∆ABC (By AA similarity)
The corresponding sides will be:
We know the value of AB and to find AC, we can use Pythagoras theoram that is:
AC = √6² + 8²
AC = 10
Coming back to the relation,
In ∆ADB, we have to find sin which is given by perpendicular/base:
Plugging the values of AD and AB,
Simplifying,
And this is our final answer.....
Carry On Learning !
