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2 years ago

If the function y = sinx is transformed to y = 3 sine (two-thirds x), how do the amplitude and period change?

Mathematics

2 answers:

icang [17]2 years ago

7 0

Answer:

Amplitude increases and the period decreases

Step-by-step explanation:

Here, we are to compare amplitude change and period change

The first equation is;

y = sin x

The second is

y = 3 sine (2/3)x

Generally, the equation of a sine graph can be written as;

y = a sin (bx + c)

where a represents the amplitude and b refers to the period

In the first equation , a = 1 while in the second , a = 3 ; This shows an amplitude increase

In the first equation, b = 1 while in the second equation b = 2/3; this shows a period decrease

damaskus [11]2 years ago

7 0

Answer:

Amplitude increases, and the period increases

Step-by-step explanation:

edge 2020

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denpristay [2]

Answer:

-73, -34, 0.5, 1.2, 23

Step-by-step explanation:

In Mathematics, the set of numbers are arranged in two ways. It means that the numbers can be arranged either in ascending order or descending order. If the numbers are arranged from the least to the greatest, then it is called ascending order. In this form, the numbers are in increasing order. The first number should be lesser than the second number.

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Answer: .0039

Step-by-step explanation:

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2 years ago

In a school of 330 students, 85 of them are in the drama club, 200 of them are in a sports team and 60 students do drama and spo

liq [111]

Let's denote students in D = in the drama club , S = in a sports team 
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2 years ago

Ms. stone buys groceries for a total of $45.32. she now has $32.25 left. which equation could be used to find out how much money

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Let x be the total money she had
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2 years ago

Jeanne wants to start collecting coins and orders a coin collection starter kit. The kit comes with three coins chosen at random

lesya692 [45]

Conditional probability is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B), or sometimes $P_B(A)$ .

The conditional probability of event A happening, given that event B has happened, written as P(A|B) is given by
$P(A|B)= \frac{P(A \cap B)}{P(B)}$

In the question, we were told that there are three randomly selected coins which can be a nickel, a dime or a quarter.

The probability of selecting one coin is $\frac{1}{3}$

Part A:
To find the probability that all three coins are quarters if the first two envelopes Jeanne opens each contain a quarter, let the event that all three coins are quarters be A and the event that the first two envelopes Jeanne opens each contain a quarter be B.

P(A) means that the first envelope contains a quarter AND the second envelope contains a quarter AND the third envelope contains a quarter.

Thus $P(A)= \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{27}$

P(B) means that the first envelope contains a quarter AND the second envelope contains a quarter

Thus $P(B)= \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}$

Therefore, $P(A|B)=\left( \frac{ \frac{1}{27} }{ \frac{1}{9} } \right)= \frac{1}{3}$

Part B:
To find the probability that all three coins are different if the first envelope Jeanne opens contains a dime, let the event that all three coins are different be C and the event that the first envelope Jeanne opens contains a dime be D.

$P(C)= \frac{3}{3} \times \frac{2}{3} \times \frac{1}{3} = \frac{6}{27} = \frac{2}{9}$

 $P(D)= \frac{1}{3}$ 

Therefore, $P(C|D)=\left( \frac{ \frac{2}{9} }{ \frac{1}{3} } \right)= \frac{2}{3}$

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