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LenaWriter [7]
1 year ago
7

A square ceiling has a diagonal of 23 ft. Shelton wants to put molding around the perimeter of the ceiling. The molding is sold

by the foot. What is the minimum amount of molding he needs? 66 ft 65 ft 17 ft 16 ft
Mathematics
2 answers:
marin [14]1 year ago
8 0

Answer:

short answer 66

Step-by-step explanation:

Hatshy [7]1 year ago
6 0

Answer:

Minimum 66 feet of molding that he needs.

Step-by-step explanation:

Given that a square ceiling has a diagonal of 23 ft.

If the sides of the square ceiling are 'a' feet, then applying Pythagoras Theorem we can write, a² + a² = 23²

⇒ 2a² = 23²

⇒ a = 16.2634 feet (Approximate)

Now, the perimeter of the square ceiling will be 4a = 65.05 feet.

If the cost of molding along the perimeter of the ceiling is in per foot, then a minimum of 66 feet of molding that he needs. (Answer)

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Compare the process of solving |x – 1| + 1 < 15 to that of solving |x – 1| + 1 > 15.
kicyunya [14]
In the first case we'd subtract 1 from both sides, obtaining |x-1|<14.

In the second case we'd also subtract 1 from both sides, and would obtain
 |x-1|>14.

What would the graphs look like?

In the first case, the graph would be on the x-axis with "center" at x=1.  From this center count 14 units to the right, and then place a circle around that location (which would be at x=15).  Next, count 14 units to the left of this center, and place a circle around that location (which would be -13).  Draw a line segment connecting the two circles.  Notice that all of the solutions are between -13 and +15, not including these endpoints.

In the second case, x has to be greater than 15 or less than -13.  Draw an arrow from x=1 to the left, and then draw a separate arrow from 15 to the right.  None of the values in between are solutions.

4 0
2 years ago
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You are in a bike race. When you get to the first checkpoint, you are 25 of the distance to the second checkpoint. When you get
Rom4ik [11]

Question:

You are in a bike race. When you get to the first checkpoint, you are 2/5 of the distance to the second checkpoint. When you get to the second check point, you are 1/4 of the distance to the finish. If the entire race is 40 miles, what is the distance between the start and the first check point?

Answer: 4 miles

Step-by-step explanation:

Let distance between start to first checkpoint = x

First checkpoint to second checkpoint = 2/5 of x

Distance of start to checkpoint 1 = ( 2/5 of start to checkpoint 2)

Distance of start to checkpoint 2 = (1/4 of start to finish)

If start to checkpoint 2 = 1/4 of start to finish

Then,

Distance of start to checkpoint 1 = ( 2/5 * 1/4 of start to finish)

Distance of start to checkpoint 1 = 2/20 of start to finish = 1/10 of start to finish

Entire race = 40 miles = distance from start to finish

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2 years ago
At a certain company, the annual winter party is always held on the second of Friday of December. What is the latest possible da
vitfil [10]

Answer:

The latest possible date is December, 14th.

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Notice that the second Friday of December is n+7, where n is the date for the first Friday of December. So, the latest the first Friday, the latest the second. As the weeks have seven days, the first Friday will be between 1st and 7th of each month. So, the latest first Friday will be 7th. Therefore, the latest second Friday will be 14th.

7 0
1 year ago
The green goober a wildly unpopular hero mixes 3 L of yellow paint was 5 L of blue plate to make a leader is a special green pai
Butoxors [25]

Answer:

<u>The equation can be y = 3b/5 or b = 5y/3</u>

Correct statement and question:

The Green Goober, a wildly unpopular superhero, mixes 3 liters of yellow paint with 5 liters of blue paint to make 8 liters of special green paint for his costume.  

Write an equation that relates the amounts (in liters) of yellow paint (y) and blue paint (b) needed to make the Green Goober's special green paint.

Source:

Previous question that can be found at brainly

Step-by-step explanation:

Let y to be the amount of liters of yellow paint needed to make the Green Goober's special green paint.

Let b to be the amount of liters of blue paint needed to make the Green Goober's special green paint.

We know that:

y:b = 3:5

Therefore,

5y = 3b, dividing by 5 at both sides we have:

y = 3b/5

And also dividing by 3 at both sides we have:

<u>b = 5y/3</u>

Both equations relate the amounts (in liters) of yellow paint and blue paint needed to make the Green Goober's special green paint.

4 0
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Answer: last notation is right N =~ P

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