System 1: The solution is (x, y) = (-4, 5)
System 2: The solution is 
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
2x + 3y = 7 ------ eqn 1
-3x - 5y = -13 --------- eqn 2
We can solve by elimination method
Multiply eqn 1 by 3
6x + 9y = 21 ------ eqn 3
Multiply eqn 2 by 2
-6x - 10y = -26 ------- eqn 4
Add eqn 3 and eqn 4
6x + 9y -6x - 10y = 21 - 26
-y = -5
y = 5
Substitute y = 5 in eqn 1
2x + 3(5) = 7
2x + 15 = 7
2x = -8
x = -4
Thus the solution is (x, y) = (-4, 5)
<h3><em><u>
Second system of equation is:</u></em></h3>
8 - y = 3x ------ eqn 1
2y + 3x = 5 ----- eqn 2
We can solve by susbtitution method
From given,
y = 8 - 3x ----- eqn 3
Substitute eqn 3 in eqn 2
2(8 - 3x) + 3x = 5
16 - 6x + 3x = 5
3x = 16 - 5
3x = 11

Substitute the above value of x in eqn 3
y = 8 - 3x

Thus the solution is 
Answer:
A. step one get the lest common multiplier for x-2, x+2 ---->(x-2)
(x+2
B.-6
Step-by-step explanation:
Answer: 20 units
Step-by-step explanation:
The distance between two points P(a,b) and Q(c,d) is given by :-

Given : The vertices of a quadrilateral = C (−2, 1), D (2, 4), E (5, 0), and F (1, −3).
Distance between points C (−2, 1) and D (2, 4) :-

Distance between points D (2, 4) and E (5, 0) :-

Distance between points E (5, 0) and F (1, −3).:-

Distance between points C (−2, 1) and F (1, −3).:-

Now, the perimeter of the quadrilateral = CD+DE+EF+FC

Answer:
The maximum area is 1,600 square meters
Step-by-step explanation:
<u><em>The complete question is</em></u>
What is the maximum area possible?
The given function area is modeled by A(w)=-w(w-80)
we know that
The given function is a vertical parabola open downward
The vertex is a maximum
The x-coordinate of the vertex represent the width for the maximum area
The y-coordinate of the vertex represent the maximum area
Convert the quadratic function in vertex form

Factor -1

Complete the square

Rewrite as perfect squares
----> function in vertex form
The vertex is the point (40,1,600)
therefore
The maximum area is 1,600 square meters