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Law Incorporation [45]
2 years ago
5

The board of directors of Saner Automatic Door Company consists of 12 members, 3 of whom are women. A new policy and procedures

manual is to be written for the company. A committee of three is randomly selected from the board to do the writing.a) What is the probability that all members of the committee are men?b) What is the probability that at least 1 member of the committee is a woman?
Mathematics
1 answer:
irakobra [83]2 years ago
4 0

Answer:

(a) The probability that all members of the committee are men is 0.3818.

(b) The probability that at least 1 member of the committee is a woman is 0.6182.

Step-by-step explanation:

The number of men in the board of directors is 9.

The number of women in the board of directors is 3.

A committee of three is randomly selected from the board.

(a)

Compute the probability that all members of the committee are men as follows:

P (Selecting 3 men) = n (Selecting 3 men) ÷ n (Selecting 3 members)

                                 =\frac{{9\choose 3}}{{12\choose 3}}\\= \frac{84}{220} \\=0.3818

Thus, the probability that all members of the committee are men is 0.3818.

(b)

Compute the probability that at least 1 member of the committee is a woman as follows:

P (At least 1 woman) = 1 - P (All 3 men)

                                 =1-0.3818\\=0.6182

Thus, the probability that at least 1 member of the committee is a woman is 0.6182.

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The claim is not fair because:

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Step-by-step explanation:

The <em>probaility</em> of an event is defined as the number of favorable outcomes divided by the number of total possible events.

P (event E) = number of outcomes for event E / number of possible events

1. <u>As </u><u>first step</u><u>, you may draw a table to find the </u><u>sample space</u><u> (set of all possible outcomes)</u>.

<u>Sample space</u>

The results of the rolling two dice are summarized in this table:

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  2                                     (2,1)  (2,2)  (2,3)  (2,4)  (2,5)  (2,6)

  3                                     (3,1)  (3,2)  <u>(3,3)</u>   (3,4)  (3,5)  (3,6)

  4                                     (4,1)   (4,2)  (4,3)  (4,4)  (4,5)  (4,6)

  5                                     (5,1)  (5,2)  (5,3)  (5,4)  (5,5)  (5,6)

  6                                     (6,1)  (6,2)  (6,3)  (6,4)  (6,5)  <u>(6,6)</u>

<u></u>

2.<u>Now, in that table, you can observe</u>:

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b) Probability of rolling two 3s: 1 / 36

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