BRAINLIEST PLZ HELP A scatter plot with a line is shown below. Graph shows numbers from 0 to 10 at increments of 1 on the x axis
and numbers from 0 to 15 at increments of 1 on the y axis. Scatter plot shows ordered pairs 0, 1 and 1, 2 and 2, 3 and 3,4 and 4, 4 and 5, 6 and 6, 8 and 7, 8 and 8, 11 and 9, 13 and 10, 15. A line joins ordered pairs 0, 0 and 10, 13.6. Which statement is most likely correct about the line? It can be the line of best fit because it is closest to most data points. It can be the line of best fit because it passes through all the scatter points. It cannot be the line of best fit because it does not pass through all the points. It cannot be the line of best fit because it does not pass through the first and last points
2 answers:
Answer:
<em>Well, Your answer will be is </em><em>B. (0,14) and (10,1).</em><em> Because, Now after plotting all the lines of given options on the graph of scatter plot we can see that the blue line y= -13/10x of Option B the is the line of best fit for this scatter plot Since it is covering almost all ordered pairs of scatter plot.</em>
<em>Hence two ordered pairs can be joined to best draw the line of best fit for this scatter plot are (0, 14) and (10, 1) </em><em>Good Luck!</em>
<em> </em>
<em>Option B is correct.</em>
<em>Here's a Photo below~.</em>
<em>From ~Itsbrazts~.</em>
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Answer:
2500 numbers
Step-by-step explanation:
Problem;
Solving for the number of 5-digit numbers divisible either by 45 or 60 but not divisible by 90;
Let us approach this in a step wise manner;
5 -digits numbers ranges from 10,000 to 99,999
To solve this problem, let us find the number of digits that are divisible by 45;
the first number divisible by 45 within this range is 10035
the last number divisible by 45 in this range is 99990
increment is 45
The total number in this range is:
+ 1 =
+ 1
= 2000 numbers
To solve this problem, let us find the number of digits that are divisible by 60;
the first number divisible by 60 within this range is 10020
the last number divisible by in this range is 99960
increment is 60
The total number in this range is:
+ 1 =
+ 1
= 1500 numbers
To solve this problem, let us find the number of digits that are divisible by 90;
the first number divisible by 90 within this range is 10080
the last number divisible by in this range is 99990
increment is 90
The total number in this range is:
+ 1 =
+ 1
= 1000 numbers
Now solution:
Number of 5 digits = number of 45 + number of 60 - number of 90
= 2000 + 1500 - 1000
= 2500 numbers