Answer:
Angle OAB = 90°
Reason: tangent theorem of a circle
Step-by-step explanation:
The diagram given shows a tangent line of the given circle with center O. The tangent touches the circle at point A.
The diagram also shows the radius of the circle, OA, drawn from the center to the circle to meet at the point of tangency.
Thus, according to the Tangent Theorem of a circle, the point at which the radius drawn from the center meets the point of tangency = 90°. The tangent is perdendicular to the radius drawn to meet at the point of tangency.
Therefore, angle OAB = 90°
solution:
Consider the curve: r(t) = t²i +(int)j + 1/t k
X= t² , y = int ,z = 1/t
Using, x = t², z = 1/t
X = (1/z)²
Xz²= 1
Using y = int, z= 1/t
Y = in│1/z│
Using x = t², y = int
Y = int
= in(√x)
Hence , the required surface are,
Xz² = 1
Y = in│1/z│
Y= in(√x)
Given:
Point A (-3.0,-5.4)
Point B (-3.0,5.4)
reflection across y-axis ⇒ (a,b) reflected (-a,b)
reflection across x-axis ⇒ (a,b) reflected (a,-b)
reflection across the origin ⇒ (a,b) reflected (-a,-b)
reflection on y = x ⇒ (a,b) reflected (b,a)
Point B is a reflection of Point A across the x-axis.
(5x^3 + 4)(25x^6 - 20x3 +16) remember factoring the cubes?
Answer:
a. ∫ xSinx dx
iii. integration by parts
u =x and dv= sinx
b. ∫ x⁴/(1+x³). dx
ii. neither
Long division is an option here before integration is done
c. ∫ x⁴. e^x³. dx
i. substitution
where u = x⁵
d. ∫x⁴ cos(x⁵). dx
i. substitution
where u = x⁵
e. ∫1/√9x+1 .dx
i. substitution
where u = 9x+1