The graph shows the rate at which the depth of the water in a pond is changing over time. On a coordinate plane, a graph titled
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Answer:
Mark the point of intersection S of circles R and P, and construct line QS.
Step-by-step explanation:
In the figure attached, the problem is shown. The construction of the tangent lines from point Q to circle P is almost done. The last step is to draw the lines that pass through point Q and the intersection of the circles.
Answer:
Step-by-step explanation:
Hello!
The variable is X: iron level on human blood.
It has a mean of μ= 51.50 mg/dl and a standard deviation of σ= 3.50 mg/dl.
According to the control chart, the process should be shut down for troubleshooting when the analysis shows values X[bar]≥ 53.42 mg/dl and X[bar]≤ 49.58 mg/dl
Warnings are received at levels X[bar]≥52.78 mg/dl and X[bar]≤ 50.22 mg/dl
The system works between levels 49.58<X[bar]<53.42 and works without warnings between 50.22<X[bar]<52.78.
Using these parameters you have to analyze if the lists of sample means to see which ones are within the working values are wich ones are outside this interval.
<u>Sample 1</u>
Min= 50.15
Max= 51.99
Mean= 51.61
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>This sample's min value is below the lower limit of the warning interval but not low enough to reach action levels, the max value is within the working range.</em>
<em><u /></em>
<u>Sample 2 </u>
Min= 50.32
Max= 52.56
Mean= 51.16
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>Both the max and min values of the sample are within the working range without warning.</em>
<em />
<u>Sample 3</u>
Min= 50.25
Max= 53.12
Mean= 51.83
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>The max value of this sample is above the upper limit of the warning interval but does not surpass the upper bond of the troubleshoot interval. Min value is within working values.</em>
<em />
<u>Sample 4</u>
Min= 50.05
Max= 53.01
Mean= 51.70
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>Both min and max values surpass the warning interval but do not reach action levels</em>.
<u>Sample 5</u>
Min= 50.35
Max= 52.71
Mean= 51.37
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>Both min and max values are within working levels without warnings.</em>
<em />
Considering that samples reaching warning levels should be shut down as a precaution, they are classified as:
Shutdown: Sample 1, 3 and 4
Do not shutdown: Sample 2 and 5.
I hope it helps!
Answer:15
Step-by-step explanation:
Given
Craftsman sell 10 Jewelry set for $500 each
For each additional set he will decrease the price by $ 25
Suppose he sells n set over 10 set
Earning
Earning
differentiate to get the maximum value
Equate to get maximum value
Thus must sell 5 extra set to maximize its earnings.