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forsale [732]
1 year ago
8

The graph shows the rate at which the depth of the water in a pond is changing over time. On a coordinate plane, a graph titled

Depth of Pond Water has Minutes on the x-axis and Feet on the y-axis. A line goes through points (2, 4) and (4, 8). The depth of the water is increasing by feet each minute.
Mathematics
1 answer:
lawyer [7]1 year ago
4 0

Answer:

Step-by-step explanation:

The key to solving this question is to find the distance bwtween the two points given

distance=y2-y1/x2-x1

(2,4)(4,8)

2=x1,4=y1

4=x2

8=y2

8-4/4-2

4/2=2

The depth of the water is increasing by 2 ft each minute

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Workers need to know the area of a park to determine how much grass seed to order. A worker drew a sketch of the park to find it
MatroZZZ [7]
The area of the park is 1465m squared, because you would find the area of the square first which is 100m squared and then you would add that to the area of the trapezoid which is 1365m squared and after you add them, you would get 1465m squared. I’m still not sure if this is the exact answer but please check it over to see if I did it correct :)
4 0
2 years ago
Read 2 more answers
The diagram shows a pentagon. It has one line of symmetry.
Nina [5.8K]

Answer:

A) 10x + 8 = 21

B) x = 1.3

Step-by-step explanation:

2(2x + 3) + 2(x + 1) + 4x = 21

4x + 6 + 2x + 2 + 4x = 21

10x + 8 = 21

10x = 13

x = 1.3 cm

7 0
1 year ago
What is the constant of variation, k, of the direct variation, y = kx, through (5, 8)? k = – k equals negative StartFraction 8 O
Reil [10]

The value of constant of variation "k" is k = \frac{8}{5} \text{ or } 1.6

<em><u>Solution:</u></em>

Given that the direct variation is:

y = kx ----- eqn 1

Where "k" is the constant of variation

Given that the point is (5, 8)

<em><u>To find the value of "k" , substitute (x, y) = (5, 8) in eqn 1</u></em>

8 = k \times 5\\\\k = \frac{8}{5}\\\\k = 1.6

Thus the value of constant of variation "k" is k = \frac{8}{5} \text{ or } 1.6

3 0
1 year ago
Read 2 more answers
A population that consists of 500 observations has a mean of 40 and a standard deviation of 15. A sample of size 100 is taken at
Alex17521 [72]

Answer:

<h3>The option D) 1.50 is correct</h3><h3>That is the standard error of the sample mean is 1.50</h3>

Step-by-step explanation:

Given that a population that consists of 500 observations has a mean of 40 and a standard deviation of 15.

A sample size is 100  taken at random from the given population.

<h3>To find the standard error of the sample mean :</h3>

From the given Mean=40 and \sigma =15

For N=100

<h3>The formula for standard error is SE_{mean}=\frac{\sigma}{\sqrt{N}}</h3>

Substitute the values in the above formula we get

SE_{mean}=\frac{15}{\sqrt{100}}

=\frac{15}{10}

=1.50

∴ SE_{mean}=1.50

<h3>∴ The standard error of the sample mean is 1.50</h3><h3>Hence the option D) 1.50 is correct</h3>
7 0
2 years ago
The random variable X = the number of vehicles owned. Find the expected number of vehicles owned. Round answer to two decimal pl
Lelechka [254]

Answer:

The expected number of vehicles owned to two decimal places is: 1.85.

Step-by-step explanation:

The table to the question is attached.

E(X) =∑xp(x)

Where:

E(X) = expected number of vehicles owned

∑ = Summation

x = number of vehicle owned

p(x) = probability of the vehicle owned

E(X) = (0 * 0.1) + (1 * 0.35) + (2 * 0.25) + (3 * 0.2) + (4 * 0.1)\\E(X) = 0 + 0.35 + 0.50 + 0.60 + 0.4\\E(X) = 1.85

The expected number of vehicles owned is 1.85.

4 0
1 year ago
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