Answer:
<h3>
- 128 Superscript StartFraction 3 Over x EndFraction
</h3><h3>
- (4RootIndex 3 StartRoot 2 EndRoot)x
</h3><h3>
- (4 (2 Superscript one-third Baseline) ) Superscript x</h3><h3>
Step-by-step explanation:</h3>
Given the indicinal equation ![(\sqrt[3]{128} )^{x}\\](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B128%7D%20%29%5E%7Bx%7D%5C%5C)
According to one of the law of indices,
![(\sqrt[a]{m} )^{b}\\= (\sqrt{m})^\frac{b}{a}](https://tex.z-dn.net/?f=%28%5Csqrt%5Ba%5D%7Bm%7D%20%29%5E%7Bb%7D%5C%5C%3D%20%28%5Csqrt%7Bm%7D%29%5E%5Cfrac%7Bb%7D%7Ba%7D)
Applying this law to the question;
![(\sqrt[3]{128} )^{x}\\ = {128} ^\frac{x}{3}\\ \\= (\sqrt[3]{64*2})^{x} \\ = (4\sqrt[3]{2})^{x} \\= (4(2^{1/3} )^{x} )](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B128%7D%20%29%5E%7Bx%7D%5C%5C%20%3D%20%7B128%7D%20%5E%5Cfrac%7Bx%7D%7B3%7D%5C%5C%20%5C%5C%3D%20%28%5Csqrt%5B3%5D%7B64%2A2%7D%29%5E%7Bx%7D%20%5C%5C%20%3D%20%284%5Csqrt%5B3%5D%7B2%7D%29%5E%7Bx%7D%20%5C%5C%3D%20%284%282%5E%7B1%2F3%7D%20%29%5E%7Bx%7D%20%29)
The following are therefore true based on the following calculation
128 Superscript StartFraction 3 Over x EndFraction
(4RootIndex 3 StartRoot 2 EndRoot)x
(4 (2 Superscript one-third Baseline) ) Superscript x
We can model the problem in many different ways.
One example is to divide 12 counters (modelled as circles) into six boxes (modelled as square)
We have two circles inside each box
The model is shown in diagram below
A. No matter what M is, it will correspond to the squared version of 18m
Answer:
$300
Step-by-step explanation:
Given that:
Derek bought a new car for $32,000;
The original amount of purchase = $32,000
Down payment = $17,000
Remaining amount = Original amount of purchase - Down payment
= $(32000 -17000)
= $ 15,000
Also;
rate of interest per month is 2%
and the Derek is unable to pay his first monthly payment
thus the interest amount is calculated on principal amount
so for the first month interest is calculated on total principal amount
The month interest payment is then calculated as :
= 15,000 × 2%
= 15,000 × 0.02
= $300
Answer:
The last two terms of the expression are
Both the last terms has variable of degree equal to (2+4=6) and (3+3=6).So, the first term must have degree greater than 6.
Correct Options are
