Which graph can be used to find the solution(s) to x2 - 4x + 4 = 2x + 1 + x??
1 answer:
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A)<span> How much would it cost to ship a package weighing 3.2 pounds? Explain how you arrived at your answer.
Answer:
Shipping cost of 3.2 package is $4.13.
</span>We can't use the cost assigned to 3 lbs because the package is over 3 lbs but it is not over 4 lbs so we use the cost of 4lbs. (check the attachment for price)
b)<span>What type of graph is needed to represent the Media Mail shipping prices as a function of the weight of the books shipped? Explain your thinking.
Answer:
Line graph </span>is needed to represent the Media Mail shipping prices as a function of the weight of the books shipped.
In line graph, x values represent the weight in pounds and the y values represent the cost.
c)<span>Graph the Media Mail shipping prices as a function of the weight of the books shipped.
Answer;
When we g</span>raph the Media Mail shipping prices as a function of the weight of the books shipped, it will be;
f(x) = 2.69 + 0.48(x-1)
Answer:
Shipping cost of 3.2 package is $4.13.
</span>We can't use the cost assigned to 3 lbs because the package is over 3 lbs but it is not over 4 lbs so we use the cost of 4lbs. (check the attachment for price)
b)<span>What type of graph is needed to represent the Media Mail shipping prices as a function of the weight of the books shipped? Explain your thinking.
Answer:
Line graph </span>is needed to represent the Media Mail shipping prices as a function of the weight of the books shipped.
In line graph, x values represent the weight in pounds and the y values represent the cost.
c)<span>Graph the Media Mail shipping prices as a function of the weight of the books shipped.
Answer;
When we g</span>raph the Media Mail shipping prices as a function of the weight of the books shipped, it will be;
f(x) = 2.69 + 0.48(x-1)
Answer:
Step-by-step explanation:
Hello!
You have two random samples obtained from two different normal populations.
Sample 1
n₁= 15
X[bar]₁= 350
S₁= 12
Sample 2
n₂= 17
X[bar]₂= 342
S₂= 15
At α: 0.05 you need to obtain the p-value for testing variances for a one tailed test.
If the statistic hypotheses are:
H₀: σ₁² ≥ σ₂²
H₁: σ₁² < σ₂²
The statistic to test the variances ratio is the Stenecor's-F test. ~
The p-value is:
P(≤0.64)= 0.02
I hope it helps!