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Vlad [161]
2 years ago
7

A radio telescope has a parabolic surface as shown below. . . A parabola opening up with vertex at the origin is graphed on the

coordinate plane. The height of the parabola from top to bottom is 1 meter and its width from left to right is 20 meters. . . If the telescope is 1 m deep and 20 m wide, how far is the focus from the vertex?.
Mathematics
2 answers:
grigory [225]2 years ago
7 0
Basing on the description, a parabola opening up with vertex at origin, the formula with vertex at origin is used, x^2 = 4py. p is the focus and so with the dimensions given, we obtain a 0.25 and that is the distance of the focus to the vertex.
mel-nik [20]2 years ago
4 0
There are several information's that are already given in the question. Based on those given information's, one can say that the origin of the parabola is opening up with the vertex of the parabola. We already know that the formula for a parabola with vertex at the origin is x^2 = 4py, where "p" is the focus. Now putting the dimensions given in the question in the formula, we get 0.25 as the correct result. I hope the answer has come to your help.

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A cube with a side 1 m long has been cut into cubes of a side 1 dm each. all small cubes have been put one on top of the other,
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First, we have to find how many small cubes formed by the large cube.
To find the number of small cubes, we should calculate the volume of each large cube and small cube. Equalize the volume units to dm³

Dimension of large cube
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Volume of large cube
v = s³
v = 10³
v = 1,000 dm³

Dimension of small cube
s = 1 dm

Volume of small cube
v = s³
v = 1³
v = 1 dm³

Second, calculate the number of small cubes formed
n = volume of large cube / volume of small cube
n = 1,000 dm³ / 1 dm³
n = 1,000
There are 1,000 small cubes.

Third, calculate the height of the structure.
The structure is formed by 1,000 cubes. Each of them is 1 dm high.
The height of the structure is
h = 1 dm × 1,000
h = 1,000 dm
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The height of the structure is 1,000 dm or 100 m
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A train traveled 260 miles in 4 hours. If the train’s average rate of travel increases by 12 mph, what is its new average rate o
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Answer:

Correct option A

Step-by-step explanation:

Average rate = 260/4 = 65 mph

It increases by 12mph

So 65+12 = 77 mph

Correct option A

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2 years ago
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Answer:

At the intersection of the first parallel line with the transversal, a = 12°, c = 168°, d = 12°, e = 168°. Counting counterclockwise from a.

At the first intersection of the second parallel line with the transversal, b = 168°, f = 12°, g = 168°, h = 12°. Counting clockwise from b.

Step-by-step explanation:

Let a be the first interior angle. Since they are in 1:14, the second same side interior angle is b = 14a.

We know that the sum of interior angles equals 180°.

So, a + b = 180°

a + 14a = 180°

15a = 180°

a = 180/15

a = 12°

At alternate angle to the other interior angle, b adjacent to a is c = b = 14a = 14 × 12 = 168°

The angle vertically opposite to a is d = a = 12°

The angle vertically opposite to a is b = e = 168°

At the intersection of the second parallel line and the transversal, the angle alternate to a is f = a = 12°

the angle vertically opposite to angle b is g = b = 168°

the angle vertically opposite to f is h = 12°

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The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section
LUCKY_DIMON [66]

Answer:

y2 = C1xe^(4x)

Step-by-step explanation:

Given that y1 = e^(4x) is a solution to the differential equation

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We want to find the second solution y2 of the equation using the method of reduction of order.

Let

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Because y2 is a solution to the differential equation, it satisfies

y2'' - 8y2' + 16y2 = 0

y2 = ue^(4x)

y2' = u'e^(4x) + 4ue^(4x)

y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)

= u''e^(4x) + 8u'e^(4x) + 16ue^(4x)

Using these,

y2'' - 8y2' + 16y2 =

[u''e^(4x) + 8u'e^(4x) + 16ue^(4x)] - 8[u'e^(4x) + 4ue^(4x)] + 16ue^(4x) = 0

u''e^(4x) = 0

Let w = u', then w' = u''

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w = C1

But w = u'

u' = C1

Integrating again, we have

u = C1x

But y2 = ue^(4x)

y2 = C1xe^(4x)

And this is the second solution

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