Answer:
See the attached figure 2.
Step-by-step explanation:
The question is as shown at the attached figure 1.
given: The garden is a right triangle with base 10 m and height 15 m.
We need to draw the garden such that 1 unit on the grid represents 2 m.
So the scale factor is 1 unit = 2 m
base = 10 m = 10/2 = 5 units
height = 15 m = 15/2 = 7.5 units
So, the garden on the grid will be a right triangle with base 5 units and height 7.5 units.
See the attached figure.
The potential energy, E, of the penny is given by E=mgh. The energy, Q, required to raise the temperature of an object by an amount ΔT is given by Q=mcΔT. We can equate these two to get the result but we must use proper units and include the 60%:
(0.6)mgh=mcΔT
We see we can divide out the mass from each side
0.6gh=cΔT, then 0.6gh/c=ΔT
(0.6)9.81(m/s²)50m/385(J/kg°C) = 0.7644°C
since this is the change in temperature and it started at 25°C we get
T=25.7644°C
As you can see the result does not depend on mass. The more massive the copper object the more potential energy it will have to contribute to the heat energy, but the more stuff there will be to heat up, and the effect is that the mass cancels.
Answer:
140y
Step-by-step explanation:
35 times a number times -4 is 35×y×(-4) which is -140y
Compab=a.b/|a|
b=<0,1,−2√10>
a.b= 2√10
|a| = √10
a.b/|a|=2√10 / √10=2
1. 28 x 3/4 = 21 kg
2. 1 hr = 60 mins
=》 1/4 hr = 60/4 = 15mins
