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VMariaS [17]
2 years ago
9

Suppose that a manager is interested in estimating the average amount of money customers spend in her store. After sampling 36 t

ransactions at random, she found that the average amount spent was $ 41.15 . She then computed a 90 % confidence interval to be between $ 38.01 and $ 44.29 .
Mathematics
1 answer:
musickatia [10]2 years ago
8 0

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The 90% confidence interval for this case would be (38.01, 44.29) and is given.

The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .

And the best option would be:

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

Step-by-step explanation:

Assuming this complete question: Which statement gives a valid interpretation of the interval?

The store manager is 90% confident that the average amount spent by the 36 sampled customers is between S38.01 and $44.29.

There is a 90% chance that the mean amount spent by all customers is between S38.01 and $44.29.

There is a 90% chance that a randomly selected customer will spend between S38.01 and $44.29.

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The 90% confidence interval for this case would be (38.01, 44.29) and is given.

The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .

And the best option would be:

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

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If y=3x^2+30x+71, then 
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y=3((x+5)^2-25)+71=3(x+5)^2-75+71=3(x+5)^2-4. So, in the first gap you can write 5 and in the second you can write -4.
Since (x+5)^2\ge 0, the minimum value of y is when (x+5)^2=0. The solution of the last equation is x=-5 and then y=-4 -- these are numbers, which you can write in the third and fourth gaps.

5 0
2 years ago
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A middle school band has 45 sixth and seventh graders The ratio of sixth to seventh graders is 2 to 3 how many sixth graders are
AnnyKZ [126]

Answer:

  18

Step-by-step explanation:

There are 2+3 = 5 ratio units representing 45 band members, so each ratio unit represents 45/5 = 9 band members.

The 2 ratio units of sixth graders represent 2×9 = 18 sixth grade band members.

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2 years ago
What are the possible numbers of positive real, negative real, and complex zeros of f(x) = −7x4 − 12x3 + 9x2 − 17x + 3?
madreJ [45]
Now, recall Descartes Rule of Signs.  Check the picture below.

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the negative real ones, come from using -x as the argument on f(x), and as you can see in the picture, there was only 1 sign change, meaning the negative real zeros are only 1.

since, based on the fundamental theorem of algebra the polynomial has 4 roots at most then,

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8 0
2 years ago
What is the finance charge on $13,300 financed at 7.9 percent for 4 years if the monthly payment per $100 is $2.44?
luda_lava [24]

If you borrowed $100, then your monthly payment is $2.44

If you borrowed $200, then your monthly payment is 2*2.44 = 4.88

etc etc

We can set up a proportion

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to figure out the monthly payment x. Cross multiply and solve for x

2.44*13300 = 100*x

100x = 2.44*13300

100x = 32452

x = 32452/100

x = 324.52

So the monthly payment is $324.52

An alternative way to get this monthly payment is to apply 2.44% to 13300, which is another way to view the phrase  "monthly payment per $100 is 2.44"

------------------

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Subtract off the principal (amount borrowed) to find the interest or finance charge: 15,576.96 - 13,300 = 2,276.96

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80%=.8

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6 0
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