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nata0808 [166]
2 years ago
9

Dolphin jump y = -16x2 + 32x - 10 This parabola has x-intercepts, representing the times when the dolphin's height above water i

s feet.
Mathematics
2 answers:
rodikova [14]2 years ago
7 0

it is -54 height above water feet

dedylja [7]2 years ago
5 0

Answer:

2 x-intercepts

Step-by-step explanation:

and  0 feet.

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What is r = wp, for p
weqwewe [10]
<span>What is r = wp, for p
</span>r = wp...divide both sides by w
so then p = r/w
3 0
2 years ago
Rachel has $25000 worth of property damage insurance. She causes $32000 worth of damage to a sports car in an accident. How much
Phoenix [80]
If you would like to know how much of the damages will the insurance company have to pay, you can calculate this using the following steps:

x% of $32000 is $25000
x% * 32000 = 25000
x/100 * 32000 = 25000
x * 320 = 25000
x = 25000 / 320
x = 78.125%

The insurance company will have to pay 78.125% of the damages.
4 0
2 years ago
Which value is closest to 85% of 25?
OverLord2011 [107]

Answer:

so the closet value will be 21.

Step-by-step explanation:

In this question we have to calculate the value of 85% of 25.

To calculate the percentage first we have to write percentage to the fraction and then multiply with 25.

\frac{85}{100} × 25

= 0.85 × 25

= 21.25

Therefore, the closet value of 21.25 will be 21 because when we round off, 0.25 will be waved off. Had this value been greater  than 0.50 or equal to 0.5 than this value would have been 22.

so the closet value will be 21.

8 0
2 years ago
Read 2 more answers
While investigating customer complaints, the customer relations department of Sonic Air found that 15 percent of the flights arr
Sonja [21]

Answer:

P(L ∩ <u>O)</u> = 0.23

Step-by-step explanation:

We are going to define the probabilistic events how:

E: Flights arrive early          P(E) =0.15

T: Flights arrive on time      P(T) = 0.25

O: Flights are overbooked  P(O) = 0.65

<u>O</u>: Flights are not overbooked

L: Flights arrive late

How  72 percent are late or not overbooked, then P(<u>O</u> ∪ L ) = 0.72

Our question is : What is the probability that the flight selected will be late and not overbooked? It means, what is P(L ∩ <u>O)</u>

This probability may be calculated how:

P(L ∩ <u>O)</u> =  P(L) + P (<u>O</u>) - P(<u>O</u> ∪ L )

   1 = P(L) + P(E) + P(O)

   1 = P(L) + 0.15 + 0.25

   P(L) = 0.6

   how P(0) = 0.65, then P(<u>O</u>) = 0.35

Thus

P(L ∩ <u>O)</u> = 0.6 + 0.35 - 0.72

P(L ∩ <u>O)</u> = 0.23

4 0
2 years ago
14.12 To determine whether training in a series of workshops on creative thinking increases IQ scores, a total of 70 students ar
pentagon [3]

Answer:

reject H₀ , {0.8262, 3.1738} at 99% C I

Step-by-step explanation:

H_0: \mu_1 = \mu_2\\H_1: \mu _1 > \mu _2\\

critical value, \alpha = 0.01

degree of freedom: 35 - 1 = 34

critical value: 2.441

from the expression

t = \frac{(x _1-x_2) - 0}{\sqrt{\frac{\sigma^{2}_x }{n_1} +\frac{\sigma^{2}_x }{n_2}  }  }

t = \frac{(110-108) - 0}{\sqrt{\frac{1.8^{2} }{35} +\frac{1.8^{2}}{35}  }  }

t = 4.648 > 2.441

H₀ is rejected because t > critical value

(b)

in the second scenario

I: (x_1 - x_2) +/- t\sqrt{\frac{\sigma^{2}_x }{n_1} +\frac{\sigma^{2}_x }{n_2}

1 - 0.99 = 0.01

\frac{\alpha }{2} = \frac{0.01}{2}= 0.005

degree of freedom = 34

t = 2.728

substituting in the above formula

we have

I: (110 - 108) +/- 2.728\sqrt{\frac{1.80^{2}}{35} +\frac{1.8^{2}}{35}}

I: 2 +/- 1.1738

I:[0.8262, 3.1738]

we can see the difference of the means is between 0.8262 and 3.1738 at 99% confidence

3 0
2 years ago
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