Answer:
=(k−1)*P(X>k−1) or (k−1)365k(365k−1)(k−1)!
Step-by-step explanation:
First of all, we need to find PMF
Let X = k represent the case in which there is no birthday match within (k-1) people
However, there is a birthday match when kth person arrives
Hence, there is 365^k possibilities in birthday arrangements
Supposing (k-1) dates are placed on specific days in a year
Pick one of k-1 of them & make it the date of the kth person that arrives, then:
The CDF is P(X≤k)=(1−(365k)k)/!365k, so the can obtain the PMF by
P(X=k) =P (X≤k) − P(X≤k−1)=(1−(365k)k!/365^k)−(1−(365k−1)(k−1)!/365^(k−1))=
(k−1)/365^k * (365k−1) * (k−1)!
=(k−1)*(1−P(X≤k−1))
=(k−1)*P(X>k−1)
Answer:
<h2>
B. 4 StartRoot 2 EndRoot i
</h2>
Step-by-step explanation:
Given the surd function √-2 and √-18, we are to fund the sum of both values.
Taking the sum:
= √-2 + √-18
= (√2 * √-1)+ (√18 *√-1)
from complex numbers, √-1) = i
The expression becomes
= √2 i+ √18 i
= √2 i+ √9*2 i
= √2 i+ 3√2 i
= 4 √2 i
= √-2 + √-18 = 4 √2 i
The result is 4 StartRoot 2 EndRoot i
<span>If Charles leaves the marina and sails his boat 10° west of north for 1.5h at 18km/h, then makes a right turn towards 60° east of north for 1.2h at 20km/h, he is 42 km from his starting point.</span>
Answer:
The expected number of coupon is 
Step-by-step explanation:
From the question we are told that
The probability that a $10 coupons delivered by mail will be redeemed is p = 0.16
The sample size is n = 10
Generally the expected number of coupons that will be redeemed is mathematically represented as
=> 
=>
Answer:
300 Adults 555 Children
Step-by-step explanation:
What we know:
Firstly, at 5pm there were 36 more Children (C) than Adults (A)
So.....C = A + 36
Secondly, at 12pm there were 5 x more Children and 4 x more Adults and the total was 855
So 4A + 5C = 855
——-
Now use ‘C = A + 36’ and get rid of all ‘C’ in the second equation.....
4A + 5C = 855
becomes......
4A + 5 (A + 36) = 855
Multiply the brackets (5 x A) and (5 x 36):
4A + 5A + 180 = 855
Take off 180 from both sides:
4A + 5A = 675
Therefore 9A = 675
Divide by 9:
A = 75
We know C is A + 36
C = 111
At 5 pm - A = 75 and C = 111
Therefore at 12:
There were 5 x C = 555
And 4 x A = 300
