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Mrrafil [7]
2 years ago
12

Four whole numbers are each rounded to the nearest 10. The sum of the four rounded numbers is 90. What is the maximum possible s

um of the original four numbers?​
Mathematics
1 answer:
qwelly [4]2 years ago
5 0

Answer:Whats the highest number each number can go up to before it rounds up? Its +4 as each number will round up otherwise. So if the rounded up numbers were 10,20,30,30. They can go up to 14,24,34,34. So its 106.please mark as brainliest

Step-by-step explanation:

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Assume there are 365 days in a year.
MissTica

Answer:

1) The probability that ten students in a class have different birthdays is 0.883.

2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.

Step-by-step explanation:

Given : Assume there are 365 days in a year.

To find : 1) What is the probability that ten students in a class have different birthdays?

2) What is the probability that among ten students in a class, at least two of them share a birthday?

Solution :

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

Total outcome = 365

1) Probability that ten students in a class have different birthdays is

The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...

\frac{364}{365}\times \frac{363}{365} \times \frac{362}{365} \times \frac{361}{365}\times\frac{360}{365} \times \frac{359}{365} \times \frac{358}{365} \times \frac{357}{365} \times\frac{356}{365}=0.883

The probability that ten students in a class have different birthdays is 0.883.

2) The probability that among ten students in a class, at least two of them share a birthday

P(2 born on same day) = 1- P( 2 not born on same day)

\text{P(2 born on same day) }=1-[\frac{365}{365}\times \frac{364}{365}]

\text{P(2 born on same day) }=1-[\frac{364}{365}]

\text{P(2 born on same day) }=0.002

The probability that among ten students in a class, at least two of them share a birthday is 0.002.

6 0
2 years ago
What is the maximum number of pages the report can have so that it can be completely stored on a USB drive that holds 4 \cdot 10
lana [24]

Answer:

<em>2,300,000pages  report.</em>

Step-by-step explanation:

Given a USB drive with memory of 4.6*10⁶KB, in order to know the maximum number of pages a report can have so that it can be completely stored on the drive, the conversion factor must be used.

We must first understand that 1 page of a document uses up approximately 2kB of the storage.

Since 2kB = 1page

4.6*10⁶KB = x page

Cross multiply

2kB * x = 4.6*10⁶KB * 1

2x =  4.6*10⁶

x =  4.6*10⁶/2

x =  2.3*10⁶

x = 2,300,000

<em>Hence the maximum number of pages that the report can have so that it can be completely stored on a USB drive that holds 4.6*10⁶KB is approximately 2,300,000pages  report.</em>

4 0
2 years ago
Which equation can you use to solve in the figure shown?
Neporo4naja [7]

What’s the figure I couldn’t see anything here.

5 0
2 years ago
Three times the sum of half Carlita's age and 3 is at least 12. What values represent Carlita's possible age?
cestrela7 [59]

Answer:

at least 6

Step-by-step explanation:

3(.5x+3)>12

1.5x+9>12

1.5>9

x>6

5 0
2 years ago
Read 2 more answers
Suzy earns $175 more per week than her roommate Katie and 125 less per week than her roommate Janine. Together the three friends
Serhud [2]
Suzy makes 675
Katie makes 500
Janine makes 800
5 0
2 years ago
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