For an investment with an interest rate compounded continuously, the formula would be
F = Pe^(rn), where r is the annual interest rate and n is the number of years.
F = 1050e^(0.055*5)
F = $1382.36
I hope I was able to answer your question.
The answer is D. All of the above.
The computational complexity of K-NN increases as the size of the training data set increase and the algorithm gets significantly slower as the number of examples and independent variables increase.
Also, K-NN is a non-parametric machine learning algorithm and as such makes no assumption about the functional form of the problem at hand.
The algorithm works better with data of the same scale, hence normalizing the data prior to applying the algorithm is recommended.
Let:
x = hours of travel
y = velocity
slope= rise/run slope=(y2-y1)/(x2-x1)
(x1,y1) = (2,50) (x2,y2) = (6,54)
sub values back into the equation m = (54-50)/(6-2) m = 1
POINT SLOPE FORMy-y1 = m(x-x1) y-50= 1(x-2) y = x -2 +50
y = x + 48
B)
the graph within the first seven hours can be obtained at point B
x = 7
y = 7+48 = 55
B(7,55)
Answer:
range is between 55.5 to 64.5
Step-by-step explanation:
Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4.5 inches
68% is 1 standard deviation from mean
To get the range of 1 standard deviation we add and subtract standard deviation from mean
mean = 60
standard deviation = 4.5
60 - 4.5= 55.5
60+4.5 = 64.5
1 standard deviation is between 55.5 to 64.5
That is 68% range is between 55.5 to 64.5
