Answer:
The perimeter is 
Step-by-step explanation:
we know that
A parallelogram is a quadrilateral where both pairs of opposite sides are parallel and equal
so
In this problem
PS=QR ----> equation A
SR=PQ ----> equation B
The perimeter of parallelogram PQRS is
P=PQ+QR+SR+PS ----> equation C
substitute equation A and equation B in equation C
we have
substitute in the formula of perimeter
We will use substitution to solve this system of linear equations, as the first equation has x and y with no coefficients, which makes it easier to find one in terms of the other. We can then substitute that value in the other equation and find the values of x and y.
x = y + 5 ---> equation 1
3x + 2y = 5 ---> equation 2
From equation 1, we get the value of x as y + 5. Using the substitution method, we can find the value of y by substituting (y+5) for x in the 2nd equation.
3(y+5) + 2y = 5
3y + 15 + 2y = 5
5y = 5 - 15
5y = -10
y = -2
Subsituting this value of y in (y+5), we can find x.
x = y + 5
x = -2 + 5
x = 3
Therefore, x = 3 and y = -2.
I will also solve this using elimination method.
Let us multiply equation 1 by 2, so that we get 2y in both equations.
2x = 2y + 10
3x + 2y = 5
Let us add both the equations.
2x + 3x + 2y = 5 + 2y + 10
5x = 15 + 2y - 2y
5x = 15
x = 3
Substituting this value of x in equation 1, we get
x = y + 5
3 = y + 5
y = 3 - 5
y = -2
Therefore, x = 3 and y = -2.
Answer:
The fraction jumped into boiling water because it wanted to be reduced.
Step-by-step explanation:
This is a maths riddle about fractions. We often see fractions that we might feel could be reduced. So, if these kinds of fractions jumps into a boiling water, they get reduced. The riddle is rather funny though.
Applying the rule for dilation, we will multiply the scale factor to its coordinates.
Having Q (0,2) and DO 0.5(x.y), the coordinates of Q' will be:
x = (.5)(0) = 0
y = (.5)(2) = 1
Therefore coordinates of Q' is (0,1)
*Having a scale factor of >1, the figure is said to be reduced.
f(x) = -5x^2 - x + 20;
f(3) = -5*3^2 - 3 + 20 = -5*9 - 3 + 20 = -45 - 3 + 20 = -28;
