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pantera1 [17]
2 years ago
6

A fair coin is flipped twice. Drag letters to complete the tree diagram to represent the sample space

Mathematics
1 answer:
ankoles [38]2 years ago
6 0

Answer:

Step-by-step explanation:

HH

HT

TH

TT

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Two quadrilaterals are congruent. One has vertices P, N, O, and M, and the other has vertices S, T, V, and U. These correspondin
Bogdan [553]

Answer: NPOM \cong VUTS and OPNM \cong TVUS will be correct.

Explanation:

Given: two quadrilaterals having verticals P, N, O,M and S,T,V,U are congruent,  where, OM is congruent or equal to TS and \angle P\cong \angle U.

in quadrilaterals NPOM and  VUTS-

since, the condition \angle P = \angle U

and, side UV=side  OM   follow for the above quadrilateral. (According to the figure)

then we can say according to the property of quadrilateral, their corresponding sides must be congruent. so they are congruent.

similarly, these two conditions also follow in the case of OPNM \cong TVUS

we can understand it by making the figures.


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1 year ago
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Find the functions y-intercept algebraically
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3 0
2 years ago
Which graph represents the function f(x) = (x – 5)2 + 3?
goblinko [34]
The function
f(x)=(x-5)^2+3
describes a parabola with vertex = (5, 3).

The graph of the function is attached.

4 0
2 years ago
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If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe
Natalka [10]

Answer:

They encircle the planet 3.76\times 10^{11} times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is 6.022\times 10^{23}

Thus, the number of dust particles is:

2.5\times 6.022\times 10^{23}=15.055\times 10^{23}

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: 10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m

If we line up the particles the distance they could cover is:

15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}

Circumference in meters:

40,076km\times \frac{1000m}{1km}=40,076,000 m

Therefore,

\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}

Hence, they encircle the planet 3.76\times 10^{11} times.

8 0
2 years ago
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