The answer is C, a perpedicular bisector. The distances of the mark along the given line are equidistance. Where the x is located, where the two dashes would intersect is where a 90 degre angle to the line would pass through.
To solve this question, you just need to count all the probability of the options.
The probability that a pitch not over the plate is a strike is zero. So, P(A | D) = 0.
True. It is 0/0+20= 0
The probability that a pitch not over the plate is a ball is 1. So, P(B | D) = 1.
True, it is 20/20+0= 1
The probability that a pitch over the plate is a strike is 10:15. So, ...
Incomplete but it sounds to be true. It should be 10/10+5= 10/15 = 2/3
The probability that a pitch over the plate is a ball is 5:10. So, P(B | C) = 0.5.
<span>B. 8.6
Let's substitute the given values into the function and calculate the result. So:
f(t) = Pe^rt
f(t) = 6e^0.06t
f(6) = 6e^(0.06*6)
f(6) = 6e^(0.36)
f(6) = 6*1.433329415
f(6) = 8.599976487
Rounding to the nearest tenth, gives: 8.6
So the answer is "B. 8.6"</span>
