This figure has two intersecting lines and a ray. What is the value of x?

A triangular prism has a base area of 7.3 square cm and a volume of 71.54 cubic cm. The height of the prism must be?

alexdok [17]

Answer:

Multiply or divide 7.3 times or divided by 71.54

3 0

2 years ago

My cupcake recipe makes $12$ cupcakes and requires $1\frac12$ sticks of butter. I can only buy whole sticks of butter. How many

andre [41]

Answer:

Given that,

My cupcake recipe makes $12$ cupcakes and requires $1\frac12$ sticks of butter. I can only buy whole sticks of butter.

Therefore, 1 whole sticks of butter is enough to make $100$ cupcakes.

8 0

1 year ago

Read 2 more answers

Helen’s house is located on a rectangular lot that is 1 1/8 miles by 9/10 mile.Estimate the distance around the lot

RUDIKE [14]

Answer:

The distance around the lot is 4.05 miles .

Step-by-step explanation:

Formula

$Perimeter\ of\ rectangle = 2 (Length + Breadth)$

As given

$Helen’s\ house\ is\ located\ on\ a\ rectangular\ lot\ that\ is\ 1 \frac{1}{8}\ miles\ by\ \frac{9}{10}\ mile.$

i.e

$Helen’s\ house\ is\ located\ on\ a\ rectangular\ lot\ that\ is\ \frac{9}{8}\ miles\ by\ \frac{9}{10}\ mile.$

Here

$Length = \frac{9}{8}\ miles$

$Breadth = \frac{9}{10}\ miles$

Put in the formula

$Perimeter\ of\ rectangle = 2(\frac{9}{8}+\frac{9}{10})$

L.C.M of (8,10) = 40

$Perimeter\ of\ rectangle = \frac{2\times (9\times 5+9\times 4)}{40}$

$Perimeter\ of\ rectangle = \frac{2\times (45+36)}{40}$

$Perimeter\ of\ rectangle = \frac{2\times 81}{40}$

$Perimeter\ of\ rectangle = \frac{81}{20}$

Perimeter of rectangle = 4.05 miles

Therefore the distance around the lot is 4.05 miles .

6 0

2 years ago

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Tony’s class needs more than $500 for the school dance. So far, they have raised $200. They plan to have a car wash, charging $8

Orlov [11]

Answer: no Tony is not correct It is less than 5 hundred dollars.

Step-by-step explanation: 8×37=296 +200 = 496

4 0

1 year ago

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A manager wants to build 3-sigma x-bar control limits for a process. The target value for the mean of the process is 10 units, a

lubasha [3.4K]

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Mean = 10

Sample size = 9

Standard deviation = 6

We need to find the upper and lower control limits.

so, Lower limit would be

$\bar{x}-3\dfrac{\sigma}{\sqrt{n}}\\\\=10-3\times \dfrac{6}{\sqrt{9}}\\\\=10-6\\\\=4$

Upper limit would be

$\bar{x}+3\dfrac{\sigma}{\sqrt{n}}\\\\=10+3\times \dfrac{6}{\sqrt{9}}\\\\=10+6\\\\=16$

Hence, Third option is correct.

3 0

2 years ago