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Kryger [21]
2 years ago
8

Each Friday, the school prints 400 copies of the school newsletter. The equation c = 400w models the relationship between the nu

mber of weeks and the total number of copies of the newsletters printed. What is true of the graph of this scenario?

Mathematics
2 answers:
Darya [45]2 years ago
6 0

AnswER

THE SECOND ONE IS ANY WHOLE NUMBER I JUST TOOK THE QUIZ

Step-by-step explanation:

lawyer [7]2 years ago
6 0

Answer and Step-by-step explanation:

The viable point on the graph is (8, 3,200).

The values of <em>w</em> must be any whole number.

<em>Hope you found this helped you out! Have a wonderful day! </em>

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What is the length of line segment EF if DE is 6ft and DF is 11ft and angle FDE is 40 degrees​
Anna [14]

Answer:

The length of EF = 7.48 feet

Step-by-step explanation:

* Lets consider these tree segment formed triangle DEF

- We have the length of two sides and the measure of the

  including angle between these two sides

* So we can use the cos Rule to find the length of the third side

- The cos rule ⇒ a² = b² + c² - 2bc cosA

# a is the side opposite to angle A

# b is the side opposite to angle B

# c is the side opposite to angle C

# Angle A is the including angle between b and c

* In the problem

∵ DE = 6 feet

∵ DF = 11 feet

∵ m∠FDE = 40° ⇒ including angle between DE and DF

  and opposite to EF

- By using cos Rule

∴ (EF)² = (DE)² + (DF)² - 2(DE)(DF) cos∠FDE

∴ (EF)² = (6)² + (11)² - 2(6)(11) cos(40)

∴ (EF)² = 55.882133 ⇒ take square root for both sides

∴ EF = 7.47543 ≅ 7.48 feet

* The length of EF = 7.48 feet

6 0
2 years ago
Write a number that is greater than 4.508 but less than 4.512
Lelechka [254]
4.509 is greater that 4.508 and less than 4.512
5 0
2 years ago
Read 2 more answers
A rectangular area is formed having a perimeter of 40 cm. Determine the length and breadth of the rectangle if it is to enclose
Vilka [71]

Let x and y be the dimensions of the rectangle. If the perimeter is 40, we have

2(x+y)=40 \iff x+y=20

We can expression one variable in terms of the others as

x+y=20 \iff x=20-y

Since the area is the product of the dimensions, we have

xy=(20-y)y=-y^2+20y

This is a parabola facing down, so it's vertex is the maximum:

f(y)=-y^2+20y \implies f'(y)=-2y+20

So, the maximum is

f'(y)=0 \iff -2y+20=0 \iff 2y=20 \iff y=10

And since we know that x+y=20, we have x=10 as well.

This is actually a well known theorem: out of all the rectangles with given perimeter, the one with the greatest area is the square.

5 0
2 years ago
Show that the three points whose position vectors are 7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k form an isosceles right
Novay_Z [31]

Answer:

AB = √18 , BC=√18 and CA =4

AB²+BC²  = CA² and AB=BC

ΔABC isosceles right  angled triangle.

Step-by-step explanation:

Given vectors are  7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k

A( 0,7,10), B( -1,6,6) C(-4,9,6)

AB⁻ = OB-OA = -I+6j+6k-(7j+10k) = -I-j-4k

AB = \sqrt{1+1+16} = \sqrt{18}

BC = OC-OB = -4i+9j+6k-(-I+6j+6k) = -3i+3j

BC=\sqrt{9+9} =\sqrt{18}

CA = OA-OC = 7j+10k - (- 4i + +9j + 6k ) = 4i-2j+4k

CA = \sqrt{16+4+16} =\sqrt{36} =4

Since AB²+BC²  = CA²

And AB=BC

Therefore it follows that ΔABC is a right angled isosceles triangle



3 0
2 years ago
If a concrete column is 6 inches by 6 inches square and 8 ft. long, calculate its weight in Newtons, given a specific weight of
tangare [24]
<h2>Weight of column is 555.83 N</h2>

Step-by-step explanation:

Size of column = 6 inch x 6 inch x 8 ft

Size of column = 0.5 ft x 0.5 ft x 8 ft

Volume of column = 0.5 x 0.5 x 8 = 2 ft³

Specific weight of concrete = 62.4 lb/ft³

Mass = Volume x Specific weight

Mass = 2 x 62.4

Mass = 124.8 lb = 124.8 x 0.454 = 56.66 kg

Weight = 56.66 x 9.81 = 555.83 N

Weight of column is 555.83 N

7 0
2 years ago
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