A car company wants to predict how much fuel different cars will use based on their masses. They took a sample of cars, drove ea
ch car 100\,\text{km}100km100, start text, k, m, end text, and measured how much fuel was used in each case (in liters). The data is summarized in the table below.
Fuel used (L) 3.6, 6.7, 9.8, 11.2, 14.7
Mass (metric tons) 0.45, 0.91, 1.36, 1.81, 2.27
All of the scatter plots below display the data correctly, but which one of them displays the data best?
By convention, a good scatter plot uses a reasonable scale on both axes and puts the explanatory variable on the x-axis.
Choose 1 answer:
(Choice A)
(Choice B)
(Choice C)
(Choice D)
Fuel used (L) 3.6, 6.7, 9.8, 11.2, 14.7
Mass (metric tons) 0.45, 0.91, 1.36, 1.81, 2.27
All of the scatter plots below display the data correctly, but which one of them displays the data best?
By convention, a good scatter plot uses a reasonable scale on both axes and puts the explanatory variable on the x-axis.
Choose 1 answer:
(Choice A)
(Choice B)
(Choice C)
(Choice D)
2 answers:
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Answer: 4
Step-by-step explanation:
Let N be the total number of runs.
The microscopes per year will be equal to the total number of runs * microscopes per run
total number of microscopes = total number of runs * microscopes per run
now we have each run to cost 2500, therefore:
run costs = 2500 * total runs = 2500*N
we also have insurance and storage costs (note the average thats why we divide by 2):
storage costs = 20* microscopes per run /2 = 20*N/2
insurance costs = 15 * microscopes per run = 15*N
the costs are:
costs = run costs + storage + insurance
now the comany sells 1600 microscopes a year, so in order to figure out the number of microscopes per run we divide 1600 by the total number of runs N and replace in the costs
costs = 2500N + 40000/N => C(N) = 2500N + 40000/N
now derivate the function with respect to N and equal to 0:
this gives you two solutions, N = -4 which is not eligible (you cant make negative microscopes lol) and N = 4 which is the answer
have a nice day