Answer:7
Step-by-step explanation:
This can be solved by Venn-diagram
Given there are total 5 students who want french and Latin
also 3 among them want Spanish,french & Latin
i.e. only 2 students wants both french and Latin only.
Also Student who want only Latin is 5
Thus Student who wants Latin and Spanish both only is 11-5-3-2=1
Students who want only Spanish is 8 Thus students who wants Spanish and French is 4
Similarly Students who wants Only French is 16-4-3-2=7
Answer:
a. z = 2.00
Step-by-step explanation:
Hello!
The study variable is "Points per game of a high school team"
The hypothesis is that the average score per game is greater than before, so the parameter to test is the population mean (μ)
The hypothesis is:
H₀: μ ≤ 99
H₁: μ > 99
α: 0.01
There is no information about the variable distribution, I'll apply the Central Limit Theorem and approximate the sample mean (X[bar]) to normal since whether you use a Z or t-test, you need your variable to be at least approximately normal. Considering the sample size (n=36) I'd rather use a Z-test than a t-test.
The statistic value under the null hypothesis is:
Z= X[bar] - μ = 101 - 99 = 2
σ/√n 6/√36
I don't have σ, but since this is an approximation I can use the value of S instead.
I hope it helps!
It’s an 6 out of 40 percent probability or 27% chance out of 100%
Answer:
c ≈ 26.4
Step-by-step explanation:
just use the pythagorean theorem
