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2 years ago

Estimate 58% of 121 by using 10%

1 answer:

5 0

58% is about equal to 60%, 10% of 121 is 12.1.
12.1 * 6 = 72.6
To take this further, 58% is 2% less than 60%, or 2 times 1%. 1% of 121 is 1.21.
72.6 - (1.21 * 2) = 72.6 - 2.42 = 70.18

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11. The sales tax rate is 6.9%

Norma-Jean [14]

Answer:

40.1%

Step-by-step explanation:

I am assuming that 192 is in 100%.

100% = 192

I then represent the value that we are looking for with $x$ .

x% = 77

By dividing both equations (100% = 192 and x% = 77) and remembering that both left hand sides of BOTH equations have the percentage unit (%).

$\frac{100}{x} = \frac{77}{192}$

Now, of course, we take the reciprocal, or inverse, of both sides:

$\frac{x}{100} = \frac{7}{192}$

x = 40.1%

Thus making the answer: 40.1% of 192 is 77.

7 0

2 years ago

Kim is reading a book with 380 pages. She read 20 pages each day until she reached Part 2 of the book. Part 2 of the book is 160

d1i1m1o1n [39]

If you divide 380 by 20, you get 19. To check this, multiply 20 x 19 to see 380. Hope this helps :D

6 0

2 years ago

Read 2 more answers

A recent study found that 51 children who watched a commercial for Walker Crisps (potato chips) featuring a long-standing sports

hichkok12 [17]

Answer:

The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

$t = 3.054$

The p-value is $p-value = P(Z > 3.054) = 0.0011291$

The conclusion is

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The test statistics is

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 51$

The first sample mean is $\mu_1 = 36$

The second sample size is $n_2 = 41$

The second sample size is $\mu_2 = 25$

The first standard deviation is $\sigma _1 = 21.4 \ g$

The second standard deviation is $\sigma _2 = 12.8 \ g$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \mu_1 = \mu_ 2$

The alternative hypothesis is $H_a : \mu_1 > \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } }$

=> $t = \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51} + \frac{ 12.8^2}{41} } }$

=> $t = 3.054$

The p-value is mathematically represented as

$p-value = P(Z > 3.054)$

Generally from the z table

$P(Z > 3.054) = 0.0011291$

=> $p-value = P(Z > 3.054) = 0.0011291$

From the values obtained we see that $p-value < \alpha$ so the null hypothesis is rejected

Thus the conclusion is

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

5 0

2 years ago

6051 was rounded to the nearest one. What is the lower bound?

shusha [124]

Answer:

6050

Step-by-step explanation:

3 0

2 years ago

there are 10 less red skittles than orange Skittles in a bag. The orange Skittles are also twice the number of red skittles. Fin

masya89 [10]

There are 20 orange skittles and 10 red skittles since 10 20 is 2 Times more than 10.