This is simply solving an equation...
You do this...
3x-7=14
+7 +7
---------------
3z=21
--- ----
3 3
z=7
hope this helped! Give me a 5-rate and a thanks if so!
Answer:
Ethan and Tenaya ate more than half of their pizza.
Sam and Suzy ate less than half of their pizza.
Step-by-step explanation:
We have been given that each of the four friends ordered individual pizzas. They ate some part of the pizzas and we have to find who ate more than half of their pizza? Less than half?
Suzy ate 3/8 of her pizza. It means she ate 0.375 of her pizza which is less than half.
Ethan ate 3/5 of his pizza. It means he ate 0.6 of his pizza which is greater than half.
Tenaya ate 4/6 of her pizza. It means she ate 0.67 of his pizza which is greater than half.
Sam ate 1/3 oh his pizza. It means he ate 0.3 of his pizza which is less than half.
Hence, we can conclude that
Ethan and Tenaya ate more than half of their pizza.
Sam and Suzy ate less than half of their pizza.
<span>We can solve the following equation: 5 x - 70 = 60, where x is the height of a kakapo in inches : 5 x - 70 + 70 = 60 + 70 ( we will add 70 to the both sides of an equation ), 5 x = 130, x = 130 : 5, x = 26 inches. We can prove it: 26 * 5 - 70 = 130 - 70 = 60 inches ( the height of an emu in inches ). Answer: The height of a kakapo is 26 inches.Hope I helped! :) Cheers!</span>
So ram had 10 chocolates and i had 30 chocolates
because 1:3= 10:30
=> 4= 40
Answer:
Σ(-1)^kx^k for k = 0 to n
Step-by-step explanation:
The nth Maclaurin polynomials for f to be
Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......
The given function is.
f(x) = 1/(1+x)
Differentiate four times with respect to x
f(x) = 1/(1+x)
f'(x) = -1/(1+x)²
f''(x) = 2/(1+x)³
f'''(x) = -6/(1+x)⁴
f''''(x) = 24/(1+x)^5
To calculate with a coefficient of 1
f(0) = 1
f'(0) = -1
f''(0) = 2
f'''(0) = -6
f''''(0) = 24
Findinf Pn(x) for n = 0 to 4.
Po(x) = 1
P1(x) = 1 - x
P2(x) = 1 - x + x²
P3(x) = 1 - x+ x² - x³
P4(x) = 1 - x+ x² - x³+ x⁴
Hence, the nth Maclaurin polynomials is
1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n
= Σ(-1)^kx^k for k = 0 to n
