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My name is Ann [436]

2 years ago

5

Students at a private liberal arts college are classified as being freshmen, sophomores, juniors or seniors, and also according

to whether they are male or female. Find the total number of possible classifications for the students of this college.

1 answer:

labwork [276]2 years ago

5 0

The total number of possible classifications for the students of this college is found by multiplying 4 (which is the classification for the year level:freshman, sophomore, juniou, senior) and 2 (which is the number of sexes: female and male). So 4 x 2 = 8. There are eight possible classifications, which are:
(Male, Freshman)
(Male, Sophomore)
(Male, Junior)
(Male, Senior)
(Female, Freshman)
(Female, Sophomore)
(Female, Junior)
(Female,Senior)

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Which of the following shows the extraneous solution to the logarithmic equation? log Subscript 4 Baseline (x) + log Subscript 4

vekshin1

<u>Given:</u>

The given equation is $\log _{4}(x)+\log _{4}(x-3)=\log _{4}(-7 x+21)$

We need to determine the extraneous solution of the equation.

<u>Solving the equation:</u>

To determine the extraneous solution, we shall first solve the given equation.

Applying the log rule $\log _{c}(a)+\log _{c}(b)=\log _{c}(a b)$ , we get;

$\log _{4}(x(x-3))=\log _{4}(-7 x+21)$

Again applying the log rule, if $\log _{b}(f(x))=\log _{b}(g(x))$ then $f(x)=g(x)$

Thus, we have;

$x(x-3)=-7 x+21$

Simplifying the equation, we get;

$x^2-3x=-7 x+21$

$x^2+4x=21$

$x^2+4x-21=0$

Factoring the equation, we get;

$(x-3)(x+7)=0$

Thus, the solutions are $x=3, x=-7$

<u>Extraneous solutions:</u>

The extraneous solutions are the solutions that does not work in the original equation.

Now, to determine the extraneous solution, let us substitute x = 3 and x = -7 in the original equation.

Thus, we get;

$\log _{4}(3)+\log _{4}(3-3)=\log _{4}(-7 \cdot 3+21)$

$\log _{4}(3)+\log _{4}(0)=\log _{4}(0)$

Since, we know that $\log _{a}(0)$ is undefined.

Thus, we get;

Undefined = Undefined

This is false.

Thus, the solution x = 3 does not work in the original equation.

Hence, x = 3 is an extraneous solution.

Similarly, substituting x = -7, in the original equation. Thus, we get;

$\log _{4}(-7)+\log _{4}(-7-3)=\log _{4}(-7(-7)+21)$

$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(49+21)$

$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(70)$

Simplifying, we get;

Undefined = $\log _{4}(70)$

Undefined = 3.06

This is false.

Thus, the solution x = -7 does not work in the original solution.

Hence, x = -7 is an extraneous solution.

Therefore, the extraneous solutions are x = 3 and x = -7

7 0

2 years ago

Read 2 more answers

Suppose that 90% of all dialysis patients will survive for at least 5 years. In a simple random sample of 100 new dialysis patie

Keith_Richards [23]

Answer:

The probability $P(\^ p > 0.80) = 0.99957$

Step-by-step explanation:

From the question we are told that

The population proportion is p = 0.90

The sample size is n = 30

Generally mean of the sampling distribution is $\mu_{\= x } = p = 0.90$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{\frac{p( -p )}{n} }$

=> $\sigma = \sqrt{\frac{0.90( 1 -0.90 )}{100} }$

=> $\sigma = 0.03$

Generally the he probability that the proportion surviving for at least five years will exceed 80%, rounded to 5 decimal places is mathematically represented as

$P(\^ p > 0.80) = P(\frac{ \^ p - p }{ \sigma } > \frac{0.80 - 0.90}{0.03} )$

Generally $\frac{\^p - p}{\sigma} = Z(The standardized \ value \ of \^ p)$

So

$P(\^ p > 0.80) = P(Z > -3.33 )$

From the z-table $P(Z > -3.33 ) = 0.99957$

So

$P(\^ p > 0.80) = 0.99957$

5 0

2 years ago