The perimeter is the sum of the enclosing side.
From the figure, the perimeter is
P = 11 + (x-2) + (11-3) + [(x-2) - (x-11)] + (x-11)
= 11 + x - 2 + 8 + 9 + x - 11
= 2x + 15
Answer: 2x + 15
The is Answer:
82
Explanation:
We observe that difference between first and second terms <span>=12−5=7</span>
Similarly difference between second and third terms <span>=19−12=7</span>
It shows that the given sequence of numbers is an arithmetic progression with common difference equal to 7.
We know that <span>nth</span> term of an AP whose first term is <span>a1</span> and whose common difference is d is given by
<span><span>an</span>=<span>a1</span>+<span>(n–1)</span>d</span>
To find the <span>12th</span> term, insert given values in the general expression
<span><span>a12</span>=5+<span>(12–1)</span>7</span>
<span><span>a12</span>=5+<span>(11)</span>7=5+77=<span>82</span></span>