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navik [9.2K]
2 years ago
11

The variables for this experiment include mass, volume and the materials in the various balls, as well as their densities. In Pa

rt II, you will be comparing an inflated football with a deflated one. Use the drop-down menus to complete the sentences and identify the independent and dependent variables. In Part II, the independent variable, the one that is intentionally manipulated, is . (mass,volume,material,density) In Part II, the dependent variable, the one that you measure the response in, is . (mass,volume,matierl,density)
Mathematics
1 answer:
jenyasd209 [6]2 years ago
3 0

Answer:the first one is volume the second one is density

Step-by-step explanation:I took the test

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Answer:

dy/dx = -1/√(1 - x²)

For 0 < y < π

Step-by-step explanation:

Given the function cos y = x

-siny dy = dx

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dy/dx = -1/siny (equation 1)

But cos²y + sin²y = 1

=> sin²y = 1 - cos²y

=> siny = √(1 - cos²y) (equation 2)

Again, we know that

cosy = x

=> cos²y = x² (equation 3)

Using (equation 3) in (equation 2), we have

siny = √(1 - x²) (equation 4)

Finally, using (equation 4) in (equation 1), we have

dy/dx = -1/√(1 - x²)

The largest interval is when

√(1 - x²) = 0

=> 1 - x² = 0

=> x² = 1

=> x = ±1

So, the interval is

-1 < x < 1

arccos(1) < y < arxcos(-1)

= 0 < y < π

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Step-by-step explanation:

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