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aleksandr82 [10.1K]
2 years ago
6

Which of the following is the best buy? a 16 oz bag of rice for $2.42 a 12 oz box of rice for $1.93 a 6 oz box of rice for $0.90

a 9 oz box of rice $1.25
Mathematics
1 answer:
Nuetrik [128]2 years ago
3 0
Divide 2.42$ by 16oz=.15125
Divide 1.93$ by 12oz=.1608333333
Divide 0.90$ by 6oz=.15
Divide 1.25$ by 9oz=.1388888889
So the cheapest per ounce would be the 9oz box of rice for $1.25
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3.<br> The perimeter of a square garden is 12 km. Find its area.
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Step-by-step explanation:

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Solve the equation y′ + 3y = t + e^(−2t).
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Hello,

I am going to remember:

y'+3y=0==>y=C*e^(-3t)

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4 0
2 years ago
Which product is positive?
Virty [35]

Answer:

(Negative two-fifths) (Negative StartFraction 8 over 9 EndFraction) (one-third) (StartFraction 2 over 7 EndFraction)

Step-by-step explanation:

(Negative two-fifths) (Negative StartFraction 8 over 9 EndFraction) (one-third) (StartFraction 2 over 7 EndFraction) = (-2/5)(-8/9)(1/3)(2/7)

Let's take the fraction and eliminate the negative sign because negative multiply negative= positive

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4 0
2 years ago
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At Pizza Perfect, Ron and Harold make pizza crusts. When they work separately Ron finishes the job of making 100 crusts 1.2 hour
Arada [10]

Answer:  Ron take approximately 4.2 hours to make 100 crusts alone.

Step-by-step explanation:

Since we have given that

Number of hours taken by Ron before Harold = 1.2 hours

Number of hours taken by Ron and Harold together = 1.8 hours

We need to find the number of hours taken by Ron alone i.e. 'x'.

Let number of hours taken by Harold alone be '1.2-x'.

Let work done by Ron alone  = \dfrac{1}{x}

Work done by Harold = \dfrac{1}{x-1.2}

According to question, we get that

\dfrac{1}{x}+\dfrac{1}{x-1.2}=\dfrac{1}{1.8}\\\\\dfrac{x-1.2+x}{x(x-1.2)}=\dfrac{1}{1.8}\\\\\dfrac{2x-1.2}{x^2-1.2x}=\dfrac{1}{1.8}\\\\3.6x-2.16=x^2-1.2x\\\\x^2-1.2x-3.6x+2.16=0\\\\x^2-4.8x+2.16=0\\\\x=0.5,4.2

x-1.2 does not satisfied with x = 0.5 so, x = 4.2

Hence, Ron take approximately 4.2 hours to make 100 crusts alone.

7 0
2 years ago
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