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olga2289 [7]
2 years ago
11

1. What is m∠CAD?

Mathematics
2 answers:
Zigmanuir [339]2 years ago
8 0

Answer:(1) The value of angle CAD is 100 degree. (2) The value of angle ABC is 95 degree.

Explanation:

(1)

According to the first given figure It is noticed that the value of angle ACB is 80 and angle ABC is 20 degree and we have to find angle CAD.

The exterior angle theorem of a triangle states that value of exterior angle is the sum of the other two interior angles.

\angle CAD=\angle ABC+\angle ACB

\angle CAD=20+80=100

Therefore, the angle CAD is 100 degree.

(2)

For second figure it is given that The measure of ∠DAB equals 125º. The measure of ∠ACB equals 30º.

By using the exterior angle theorem of a triangle, we can say that,

\angle BAD=\angle ABC+\angle ACB

125=\angle ABC+30

\angle ABC=125-30

\angle ABC=95

Therefore, the angle ABC is 95 degree.

bulgar [2K]2 years ago
6 0
< CAD = 100....if u add < ACB + < CBA u get < CAD
================
< DAB = 125 and < ACB = 30

if DAB = 125.....then BAC = 180 - 125 = 55
and all 3 interior angles of a triangle = 180
< BAC + < ACB + < ABC = 180
55 + 30 + < ABC = 180
85 + < ABC = 180
< ABC = 180 - 85
< ABC = 95 <===


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768 libras de fuerza

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w = peso del coche

s = velocidad de los coches

En la pregunta se nos dice:

La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.

F ∝ 1 / r

Y luego con el peso del auto

F ∝ w

Y el cuadrado de la velocidad del coche

F ∝ s²

Combinando las tres variaciones juntas,

F ∝ 1 / r ∝ w ∝ s²

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F = k × w × s² / r

F = kws² / r

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Encuentra k

En la pregunta, se nos dice:

Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.

F = 400 libras

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Tenga en cuenta que desde el

F = kws² / r

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Paso 2

¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?

F = ?? libras

w = ya que es el mismo carro = 1600 libras

r = 600

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F = kws² / r

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F = 2/25 × 1600 × 60² / 600

F = 768 libras

Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.

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