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2 years ago

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Last year,Mark was 46 inches tall.This year,Marks height is 3 inches less than peters height.Peter is 51 inches tall.How tall is

mark?
Write an equation to represent the situation.
Then solve the equation to answer the problem.

2 answers:

In-s [12.5K]2 years ago

7 0

Im not sure abbout the equations... but Mark is 48 inches, cuz it says; He WAS 46 in. tall. this year, amrks height is 3 inches LESS than peters height. So now, peter is 51 in. tall How tall is mark NOW? So u just have to minus 51-3 = 48!

zvonat [6]2 years ago

4 0

I think the equation is 51-3=49

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A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past

Volgvan

Answer: We reject the null hypothesis, and we use Normal distribution for the test.

Step-by-step explanation:

Since we have given that

We claim that

Null hypothesis : $H_0:\mu\geq 50000$

Alternate hypothesis : $H_1:\mu$

There is 5% level of significance.

$\bar{X}=46800\\\\\sigma=9800\\\\n=29$

So, the test statistic would be

$z=\dfrac{\bar{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\z=\dfrac{46800-50000}{\dfrac{9800}{\sqrt{29}}}\\\\z=-1.75$

Since alternate hypothesis is left tailed test.

So, p-value = P(z≤-2.31)=0.0401

And the P-value =0.0401 is less than the given level of significance i.e. 5% 0.05.

So, we reject the null hypothesis, and we use Normal distribution for the test.

4 0

2 years ago

Fudgin [204]

Answer:

A. $301

B. $721

Step-by-step explanation:

Let $x be the amount of money they raised.

Rowena tried to put the $1 bills into two equal piles and found one left over at the end, then

$x=2q_1+1$

Polly tried to put the $1 bills into three equal piles and found one left over at the end, then

$x=3q_2+1$

Frustrated, they tried 4, 5, and 6 equal piles and each time had $1 left over, then

$x=4q_3+1\\ \\x=5q_4+1\\ \\x=6q_5+1$

Finally Rowena put all the bills evenly into 7 equal piles, and none were left over, then

$x=7q_6$

This means $x-1$ is divisible by 2, 3, 4, 5 and 6 without remainder, so

$x-1=2\cdot 3\cdot 2\cdot 5n=60n$

Hence,

$x=60n+1, \ n\in N$

The smallest amount of money they could have raised is $301, because

$x=60\cdot 5+1=301$ is divisible by 7.

Now, the number $x=60n+1$ should be divisible by 7 and must be greater than 500.

So,

$60n+1>500\\ \\60n>499\\ \\n>8$

When n = 9,

$x=60\cdot 9+1=541$ is not divisible by 7.

When n = 10,

$x=60\cdot 10+1=601$ is not divisible by 7.

When n = 11,

$x=60\cdot 11+1=661$ is not divisible by 7.

When n = 12,

$x=60\cdot 12+1=721$ is divisible by 7.

B. The least amount of money they could have raised is $721

7 0

2 years ago

Read 2 more answers

Find ST if S(-3,10) and T(-2,3)

Aleonysh [2.5K]

Answer:

ST = 7.07 units

Step-by-step explanation:

* Lets explain how to find the length of a segment

- The length of a segment whose endpoints are $(x_{1},y_{1})$

and $(x_{2},y_{2})$ can be founded by the rule of the distance

$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

* Lets solve the problem

∵ The line segment is ST

∵ S is (-3 , 10)

∵ T is (-2 , 3)

- Assume that S is $(x_{1},y_{1})$ and T is $(x_{2},y_{2})$

∴ $x_{1}=-3$ and $x_{2}=-2$

∴ $y_{1}=10$ and $y_{2}=3$

- By using the rule above

∴ $ST=\sqrt{(-2--3)^{2}+(3-10)^{2}}$

∴ $ST=\sqrt{(1)^{2}+(-7)^{2}}$

∴ $ST=\sqrt{1+49}$

∴ $ST=\sqrt{50}$

∴ ST = 7.07 units

6 0

2 years ago

Read 2 more answers

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

Troyanec [42]

The domain is the x values

y = 2 - x

when x = -3
y = 2 - (-3)
y = 2 + 3
y = 5....so ur points are (-3,5)

when x = -2
y = 2 - (-2)
y = 2 + 2
y = 4....so ur points are (-2,4)

when x = -1
y = 2 - (-1)
y = 2 + 1
y = 3...so ur points are (-1,3)

when x = 0
y = 2 - 0
y = 2....so ur points are (0,2)

when x = 1
y = 2 - 1
y = 1...so ur point are (1,1)

so basically, u plot all of those points

7 0

2 years ago

terry wants to buy 3 eggplants. The eggplants weigh a total of 3 3/4 pounds. about how much will the eggplants cost?

Mrrafil [7]

You are required to find the weight of each eggplant

The weight of each eggplant is 5/4 pounds

Let

Number of eggplant = 3

Total <em>Weight</em> of eggplant = 3 3/4 pounds

Weight of each eggplant = Total Weight of eggplant ÷ Number of eggplant

= 3 3/4 ÷ 3

= 15/4 ÷ 3

= 15/4 × 1/3

= (15 × 1) / (4 × 3)

= 15/12

= 5/4 pounds

Weight of each eggplant = <em>5/4 pounds</em>

Read more:

brainly.com/question/18549782

8 0

1 year ago