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garri49 [273]
1 year ago
7

A teacher keeps track of the number of students that participate at least three times in an optional study session each year. He

models the attendance over the last nine years with this function. n(t) = 3.53t^2 - 33.04t + 117.56 Which graph would most likely be associated with the given model?

Mathematics
2 answers:
Anastasy [175]1 year ago
6 0

Answer:

It is not C got it wrong.

Step-by-step explanation:

aev [14]1 year ago
3 0

Answer:

its B

Step-by-step explanation:

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Billy had 55 stamps in his collection. billy’s older brother tommy had 73 stamps in his collection. how many stamps did the two
Rudik [331]
No.of stamps Billy had = 55

Number of stamps Billy's older brother had = 73

So total number of stamps two brother have together = 73 + 55
                                                                                     = 128

6 0
2 years ago
PLEASE HELP!! Jackson relies on his customers to tell their friends about his business. His business grows as each customer cont
Andrew [12]

Answer:

a) <u><em>y = 9.187 * 1.09899^x</em></u>

b) <u><em>2647.2695</em></u>

Step-by-step explanation:

a) using calculator, (mine is ti84 plus ce), we use stat and edit. we plug in x and y. x will be in the L1 and y wil be in L2. Now, we go to stat, calc,  and we press ExpReg, short for exponential regression. we calculate and get <u><em>y = 9.187 * 1.09899^x</em></u>

you can round if you want. well, i guess you shouldn't, cuz it changes it dramatically

b) Now, we use <u><em>y = 9.187 * 1.09899^x </em></u> into the y= and we put it in whatever slot we want. Now, we press trace. we press 60 to find the y,because the number is always x. the number , y, we want is <u><em>2647.2695</em></u> recommendations.

4 0
2 years ago
Work out (7x10^5)divide(2x10^2) give your answer in standard form (I WILL GIVE BRAINLIEST)
mariarad [96]
The answer to ur problem is 3.5x10^3
6 0
2 years ago
"High tides at a beach occur at intervals of 12 h 25 min. Yesterday, high tide was measured at 5 ft above sea level and low tide
lions [1.4K]

Answer:

13

Step-by-step explanation:

5 0
2 years ago
Bogle Company purchased machinery for $320,000 on January 1, 2014. Straight-line depreciation has been recorded based on a $20,0
horrorfan [7]

Answer:

$66,000

Step-by-step explanation:

Data provided in the question:

Purchasing cost of the machine = $320,000

Salvage value = $20,000

Useful life of the machine = 5 years

The gain on selling of the machine = $6,000

Now,

The annual depreciation of the machine

= [Cost - salvage value] ÷ ( Useful life )

= [ $320,000 - $20,000 ] ÷ 5

= $60,000

Accumulated depreciation from January 1, 2014 to May 1, 2018

= Annual depreciation ×  (Duration from January 1, 2014 to May 1, 2018 )

= $60,000 × ( 4 years 4 months )

= $60,000 × \frac{52}{12} years      

[48 months + 4 months = 52 months]

= $260,000

Therefore,

Book value on May 1, 2018 = Cost - Accumulated depreciation

= $320,000 - $260,000

= $60,000

Now,

Gain = Selling cost - Book value

$6,000 = Selling cost - $60,000

or

Selling cost = $66,000

Hence,

cash Bogle received from the sale of the machinery was $66,000

7 0
2 years ago
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