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Contact [7]
2 years ago
13

Given: AB ∥ DC

Mathematics
1 answer:
RSB [31]2 years ago
5 0

Answer:

A=1,720.16\ units^2

Step-by-step explanation:

we know that

The area of the trapezoid is equal to

A=\frac{1}{2}(DC+AB)DE

step 1

Find the measure of angle DAE

m∠ADC+m∠DAE=180° -----> by consecutive interior angles

we have

m∠ADC = 134°

substitute

134°+m∠DAE=180°

m∠DAE=180°-134°=46°

step 2

In the right triangle ADE

Find the length side AE

cos(∠DAE)=AE/AD

AE=cos(46\°)(40)\\AE=27.79\ units

step 3

In the right triangle ADE

Find the length side DE

sin(∠DAE)=DE/AD

DE=sin(46\°)(40)\\DE=28.77\ units

step 4

Find the area of ABCD

A=\frac{1}{2}(DC+AB)DE

we have

DC=32\ units\\AB=DC+2(AE)=32+2(27.79)=87.58\ units\\DE=28.77\ units

substitute

A=\frac{1}{2}(32+87.58)28.77

A=1,720.16\ units^2

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Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. A = 46°, b
horrorfan [7]
We will use the law of cosines
<span>side a² = b² + c² -2bc • cos(A)
</span><span>side a² = 729 + 196 -2*27*14 * cos (46)
</span><span>side a² = 925 -(756 * 0.69466)
</span>side a² = <span><span>399.83704 </span>
side a = </span><span><span><span>19.995925585 </span> </span> </span>
We could round that to 20
a = 20 b = 27 c =14

We can calculate a triangle's area when we know all 3 sides by using Heron's Formula
<span>area = square root (s • (s - a) • (s - b) • (s - c))

where s is the semi-perimeter </span>
semi-perimeter<span> = (side a + side b + side c) ÷ 2</span>
s = (20 + 27 + 14) / 2
s = 30.5
Now we use Heron's Formula
area = square root (s • (s - a) • (s - b) • (s - c))
area = square root (30.5 • (<span>30.5 - 20) • (</span><span>30.5 - 27) • (</span><span>30.5 - 14))</span>
area = square root (30.5 • (10.5) • (3.5) • (<span>16.5))</span>
<span>area = square root (18494.4375)
</span> <span><span><span>area = 135.9942553934  </span> </span> </span>which rounds to
136 square feet
Source:
http://www.1728.org/triang.htm

 




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1 year ago
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