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inessss [21]
1 year ago
8

Solve the equation. Negative StartFraction 9 Over 15 EndFraction y + StartFraction 3 Over 21 EndFraction = StartFraction 5 Over

15 EndFraction y minus StartFraction 14 Over 21 EndFraction What is the solution?
Mathematics
2 answers:
AleksandrR [38]1 year ago
6 0

Answer:

y=85/98

Step-by-step explanation:

Solve the equation.

Negative StartFraction 9 Over 15 EndFraction y + StartFraction 3 Over 21 EndFraction = StartFraction 5 Over 15 EndFraction y minus StartFraction 14 Over 21 EndFraction

What is the solution?

y = StartFraction 68 Over 315 EndFraction

y = StartFraction 31 Over 105 EndFraction

y = StartFraction 85 Over 98 EndFraction

y = StartFraction 85 Over 28 EndFraction

mina [271]1 year ago
4 0

Answer:

Step-by-step explanation:

9/15y + 3/21 = 5/15 y - 14/21. Adding 14/21 to both sides we then get 9/15y + 17/21 = 5/15y. Subtracting 5/15y from both sides, we get 4/15y + 17/21 = 0.

Then we get 4/15y = -17/21. Dividing by 4/15 gets us -17/21 * 4/15 = -68/315 = y.

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Alex
I see the solution in three steps.
1.) RS ⊥ ST, RS ⊥ SQ, ∠STR ≅ ∠SQR | Given
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5 0
1 year ago
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the area of a trapezium is 594 sq. cm. The lengths of its parallel sides are in the ratio 4 : 5. The height of the trapezium is
Sophie [7]

Answer:

1st side=44 cm, 2nd side= 55cm

Step-by-step explanation:

let a = '4x' , b = '5x'

h= 12cm

Area of trapezium=1/2*(a+b)h

area=594=1/2*9x*12

594*2/12=9x

594/6=9x

99=9x

99/9=11=x

therefore, 4x=4*11=44cm

             &5x=5*11=55cm

5 0
1 year ago
Determine the value of $a$. [asy] pair w=(0,4); pair x=(0,0); pair y=(4,0); pair z=y+7/sqrt(2)*(1,1); dot(w); dot(x); dot(y); do
grandymaker [24]

Answer:

a=7

Step-by-step explanation:

The image is rendered and attached below.

Triangle WXY is an Isosceles right triangle, since WX=XY.

First, we determine the length of WY using Pythagoras Theorem.

WY=\sqrt{4^2+4^2}\\WY=\sqrt{32}

Since triangle WXY is Isosceles, \angle XYW=45^\circ

\angle XYZ=\angle XYW+\angle WYZ\\135^\circ=45^\circ+\angle WYZ\\\angle WYZ=135^\circ-45^\circ=90^\circ

Therefore:

Triangle WYZ is a right triangle with WZ as the hypothenuse.

Applying Pythagoras Theorem

WZ^2=WY^2+YZ^2\\9^2=(\sqrt{32})^2+a^2\\a^2=81-32\\a^2=49\\a^2=7^2\\$Therefore: a=7

3 0
2 years ago
Sheri’s cab fare was $32, with a 20% gratuity and no taxes. Sheri wrote a check to the cab driver for $40.
stira [4]

Yes, $40 is a reasonable amount to pay for the cab fare.

<em><u>Explanation</u></em>

Sheri’s cab fare was $32 and the percentage of gratuity is 20%

So, the amount of gratuity will be: \$32* 20\% = \$32*0.20= \$6.40

Thus, <u>the fare of the cab including the gratuity</u> will be:  \$32+\$6.40 = \$38.40

As Sheri wrote a check to the cab driver for $40 , it means she paying ($40 - $38.40) or <u>$1.60 more to the cab driver</u>. So, the $40 check is a reasonable amount to pay for the cab fare.

5 0
2 years ago
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Which equation can be used to find the length of Line segment A C? Triangle A B C is shown. Angle A C B is 90 degrees and angle
taurus [48]

<u><em>Answer:</em></u>

AC = 10sin(40°)

<u><em>Explanation:</em></u>

The diagram representing the question is shown in the attached image

Since the given triangle is a right-angled triangle, we can apply the special trig functions

<u>These functions are as follows:</u>

sin(θ) = opposite / hypotenuse

cos(θ) = adjacent / hypotenuse

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θ = 40°

AC is the side opposite to θ

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<u>Based on these givens</u>, we will use the sin(θ) function

<u>Therefore:</u>

sin(40) = \frac{AC}{10}\\ \\AC = 10sin(40)

5 0
2 years ago
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