Total number of pens = (20 pens/box)*(number of boxes)
I hope the equation will be 2000=16000(1-r)^t because t is missing in the equation which we need to find.
Given rate: r= 35%= 0.35.
So, first step is to plug in 0.35 for r in the given formula to get the value of t.
Hence, the equation will be:
2000=16000(1-0.35)^t
2000=16000(0.65)^t (By subtraction)
2000/16000= 16000(0.65)^t /16000 (Dividing each sides by 16000)
0.125 = 0.65^t (By simplifying).
log 0.125 = log 0.65^t (Taking log each sides to isolate t).
log 0.125 = t log 0.65 (By applying the log property).
(Dividing each sides by log 0.65)
-0.903/-0.187 =t
t= 4.83
t= 5 ( Rounded to nearest integers)
So, Devon's car is 5 years old.
So first we will add together the fractions. 3/4 is equal to 6/8, so we will add 6/8 to 7/8 and get 13/8, or 1 5/8. Then we can add together the whole numbers, 19 and 18, to get 37. Then add 37 + 1 5/8 and get 38 5/8. Lastly, we subtract that amount from 50 to get a finale number of 11 3/8. The pet store donated 11 3/8 pounds of cat food! Hope this helps!
Though I almost broke my brain while solving what "-3 0 -2 5 0 9 2 5 3 0" means, I can tell you which statements is absolutely incorrect: it is "The function g(x) has a minimum value of 0" (it is incorrect because the maximum value is 9 as table provides).
To solve other problems, look at f(x): if it has the top, where y is the biggest, then it is the maximum value (so if y = 4.5 is the biggest y, first statement is correct); if it has the bottom, where y is the smallest, then it is minimum value (factually, statement 3 will be correct if statement 1 is correct because 9/4.5 = 2). Finally, if f(x) has the top, then statement 4 is correct because f(x) and g(x) would be both constantly decreasing functions.
Hope this helps.
Answer:
Which graph is the result of reflecting f(x) = One-fourth(8)x across the y-axis and then across the x-axis?
On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and incresaes into quadrant 1. It goes through the y-axis at (0, 0.25) and goes through (1, 2).
On a coordinate plane, an exponential function approaches y = 0 in quadrant 1 and increases in quadrant 2. It crosses the y-axis at (0, 0.25) and goes through (negative 1, 2).
On a coordinate plane, an exponential function approaches y = 0 in quadrant 3 and decreases into quadrant 4. It crosses the y-axis at (0, negative 0.25) and goes through (1, negative 2).
On a coordinate plane, an exponential funtion increases in quadrant 3 into quadrant 4 and approaches y = 0. It goes through (negative 1, negative 2) and crosses the y-axis at (0, negative 0.25).
Step-by-step explanation: