(x) = arcsec(x) − 8x
f'(x) = d/dx( arcsec(x) −
8x )
<span> 1/xsqrt( x^2 - 1) - 8</span>
f'(x) = 0
1/xsqrt( x^2 - 1) - 8 = 0
8 x sqrt (x^2-1) = 1
<span> ( 8 x sqrt (x^2-1) )^2 = 1</span>
64 x^2 ( x^2 - 1) = 1
64 x^4 - 64 x^2 =1
64 x^4 - 64 x^2 - 1 = 0
x = 1.00766 , - 1.00766
<span> x = - 1.00766</span>
f(- 1.00766) = arcsec(-
1.00766) − 8( - 1.00766)
f( - 1.00766 ) = 11.07949
x = 1.00766
f(1.00766) =
arcsec(1.00766) − 8( 1.00766)
f(1.00766 ) = -7.93790
relative maximum (x, y) =
(- 1.00766 , 11.07949 ) relative minimum (x, y) = ( 1.00766 ,
-7.93790 )
The correct answer would be choice A: 1.
When 3 coins are flipped, there are 8 possible outcomes.
0 Tails = 1 ways
1 Tails = 3 ways
2 Tails = 3 ways
3 Tails = 1 ways
If you add up all the different tails, you could get 12 tails. Divide 12 by 8 and you have 1.5 which is the average number of tails you could expect to get by flipping 3 coins.
Answer:
Step-by-step explanation:
Hello, please consider the following.
A. (x minus y)(y minus x)

This is not a difference of squares.
B. (6 minus y)(6 minus y)

This is not a difference of squares.
C. (3 + x z)(negative 3 + x z)
This is a difference of squares.

D. (y squared minus x y)(y squared + x y)
This is a difference of squares.

E. (64 y squared + x squared)(negative x squared + 64 y squared)
This is a difference of squares.

Hope this helps.
Do not hesitate if you need further explanation.
Thank you
h=5 in
w-6 in
l=12 in
SA/V=2*12*6+2*6*5+2*12*5/12*6*5
817:180
This is just an example do not use this exact equation and number! Hope it helps. : )
Answer:
The number of ways is equal to 
Step-by-step explanation:
The multiplication principle states that If a first experiment can happen in n1 ways, then a second experiment can happen in n2 ways ... and finally a i-experiment can happen in ni ways therefore the total ways in which the whole experiment can occur are
n1 x n2 x ... x ni
Also, given n-elements in which we want to put them in a row, the total ways to do this are n! that is n-factorial.
For example : We want to put 4 different objects in a row.
The total ways to do this are
ways.
Using the multiplication principle and the n-factorial number :
The number of ways to put all 40 in a row for a picture, with all 12 sophomores on the left,all 8 juniors in the middle, and all 20 seniors on the right are : The total ways to put all 12 sophomores in a row multiply by the ways to put the 8 juniors in a row and finally multiply by the total ways to put all 20 senior in a row ⇒ 