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Ilia_Sergeevich [38]
1 year ago
5

a polynomial has been factored below, but some constants are missing. 2x^3-2x^2-24x=ax(x+b)(x+c) what are the missing values of

a,b, and c?

Mathematics
2 answers:
otez555 [7]1 year ago
6 0
Hello here is a soluion : 

Eduardwww [97]1 year ago
4 0

Answer:

a=2, b= -4, c=3

Step-by-step explanation:

2x^3-2x^2-24x=ax(x+b)(x+c)

Find out the constants a,b and c

LEts factor the given expression

2x^3-2x^2-24x

GCF is 2x

2x(x^2-x-12)

Factor out x^2-x-12

Product is -12 and sum is -1

-4 times 3 is -12

-4 plus 3 is -1

x^2-x-12 = (x-4)(x+3)

2x(x^2-x-12)

2x(x-4)(x+3)

The value of 'a' is 2

'b' is -4 and 'c' is 3

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\hat{p}\pm z^* \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}= 0.61\pm 0.61\sqrt{\frac{0.61(1-0.61)}{1578}}=0.61\pm 0.024 \ or (0.586, 0.634).

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Answer:

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In order to solve this question we will use Binomial  probability distribution because:

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Number of outcomes of this distributions are two.

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