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anyanavicka [17]
1 year ago
9

This year I will have 180 hours free in which I can watch TV or watch movies. Each movie lasts 2 hours, and I'll be able to watc

h each TV show for 20 hours. I have $600; each movie costs $10, and each game costs $40.
(a) If I make 3 new friends every time I get a new video game, and 1 new friend every time I watch a movie, how many movies should I watch this year to maximize the number of new friends I make?
(b) If I instead make 5 new friends every time I get a new video game but I still make 1 friend per movie, then how many movies should I watch this year to maximize the number of new friends I make?
(c) Suppose I want to make as many new friends as possible. What is the smallest whole number of new friends each new video game must give me (assume I make the same number of new friends for each game I buy and that I make 1 friend per movie) in order for it to make sense for me to buy only video games this year?
Mathematics
1 answer:
bekas [8.4K]1 year ago
5 0

Step-by-step explanation:

ESLAC  

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Answer:

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}} \times \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{\sqrt{30} - \sqrt{18} + \sqrt{55} - \sqrt{33}}{2}

Step-by-step explanation:

Let's translate what you've written in words to an expression with mathematical symbols.

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}}

To solve this, you need to multiply both the numerator and denominator with the conjugate of the denominator.

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}} \times \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{\sqrt{30} - \sqrt{18} + \sqrt{55} - \sqrt{33}}{2}

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Hello : 
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the table shows the number of minutes Tim has for lunch and study hall. he calculates that these two periods account for 18% of
EleoNora [17]

Tim spends 500 minutes at the school.

Step-by-step explanation:

Given,

Time for lunch = 45 minutes

Time for study hall = 45 minutes

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Let,

x be the total minutes Tim spend at school.

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Keywords: percentage, division

Learn more about division at:

  • brainly.com/question/101683
  • brainly.com/question/103144

#LearnwithBrainly

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