Answer:
Step-by-step explanation:
Data given and notation
represent the sample mean
represent the standard deviation for the sample
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to determine if the mean is less than 56, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
Based on the conditions given above, the number of bacteria at any time t (in hours) is calculated by the equation,
at = (a1)(2^t/2)
where a1 is the initial number of bacteria and at is the number at any time t. Substituting the givens,
a6 = (103)(2^6/2) = 824
Thus, there are 824 bacteria after 6 hours.
Answer:
40
Step-by-step explanation:
20 + 2.5x = 3x
20 = 0.5x
x = 40
Area = perimeter + 132.
Let each side of the city be x miles long, then:-
x^2 = 4x + 132
x^2 - 4x - 132 = 0
x = [-(-4) +/- sqrt((-4)^2 - 4 * 1 *-132)] / 2
x = 13.66, -9.66 We ignore the negative
So the city has dimension of 13.66 * 13.66
13.7 * 13.7 to nearest 10th
