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FrozenT [24]
2 years ago
14

Suppose students' ages follow a skewed right distribution with a mean of 24 years old and a standard deviation of 3 years. If we

randomly sample 350 students, which of the following statements about the sampling distribution of the sample mean age is incorrect?
a. The shape of the sampling distribution is approximately normal.
b. The mean of the sampling distribution is approximately 24-years old.
c. The standard deviation of the sampling distribution is equal to 5 years.
d. All of the above statements are correct.
Mathematics
1 answer:
natta225 [31]2 years ago
8 0

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

Mean of students' age = 24 years

Standard deviation of students' age = 3 years

Sample size = number of students = 350

So, according to options,

a. The shape of the sampling distribution is approximately normal.

It is true as n >30, we will use normal.

b. The mean of the sampling distribution is approximately 24-years old.

It is true as it is given.

c. The standard deviation of the sampling distribution is equal to 5 years.

It is not true as it is given 3 years.

Hence, Option 'c' is correct.

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Im pretty sure its
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2 years ago
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The number of hours Layla worked each week for the first eight weeks of summer break are recorded below.
Rainbow [258]

Answer: The value of the center increases and the distribution has a smaller spread.

Step-by-step explanation:

Re - arranging the first value in ascending order , we have :

12 ,14, 16 , 19, 21 , 22 , 28 , 32

Median = 19 + 21 / 2

            = 40/2

            = 20

Also calculating the standard variation in order to know the spread , we need to first of all calculate the mean

Mean = 12 + 14 + 16 + 19 + 21 + 22 + 28 + 32  / 8

Mean = 164/8

Mean = 20.5

Therefore to calculate the standard deviation, we need to calculate the variance, which  is

(12-20.5)^{2} +(14-20.5)^{2} + (16-20.5)^{2} + (19-20.5)^{2} + (21-20.5)^{2} + (22-20.5)^{2} + (28-20.5)^{2} + (32-20.5)^{2}  / 8

Variance = 328/8

Variance = 41

Standard deviation = \sqrt{variance}

S.D = \sqrt{41}

S.D = 6.4

Also re arranging the second values , we have :

20 , 24 , 25 , 31

Median = 24 + 25 / 2

Median = 49/2

Median = 24.5

Calculating the S.D using the same format , the S.D = 3.9

Comparing the two we can conclude that the value at the center increases and the distribution has a smaller spread

8 0
2 years ago
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Kay buys 12 pounds of apples. Each pound costs $3.if she gives the cashier two $20 bills, how much change should she receive.
zlopas [31]

12 pounds x $3 = $36

$40 - $36 = $4

7 0
2 years ago
Using V = lwh, what is an expression for the volume of the following prism? The dimensions of a prism are shown. The height is S
Lubov Fominskaja [6]
<h2>Explanation:</h2><h2></h2>

We know that the volume of a prism is defined by:

V=lwh \\ \\ \\ Where: \\ \\ l:length \\ \\ w:width \\ \\ h:height \\ \\ \\ l=\frac{d-2}{3d-9} \\ \\ w=\frac{4}{d-4} \\ \\ h=\frac{2d-6}{2d-4}

Substituting values:

V=\left(\frac{d-2}{3d-9}\right)\left(\frac{4}{d-4}\right)\left(\frac{2d-6}{2d-4}\right) \\ \\ \\ Simplifying: \\ \\ V=\frac{d-2}{3d-9}\cdot \frac{4}{d-4}\cdot \frac{d-3}{d-2} \\ \\ V=\frac{\left(d-2\right)\cdot \:4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)\left(d-2\right)} \\ \\ V=\frac{4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)} \\ \\ V=\frac{4\left(d-3\right)}{3\left(d-3\right)\left(d-4\right)}

Finally: \\ \\  \boxed{V=\frac{4}{3\left(d-4\right)}}

4 0
2 years ago
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the area of a trapezium is 594 sq. cm. The lengths of its parallel sides are in the ratio 4 : 5. The height of the trapezium is
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Answer:

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Step-by-step explanation:

let a = '4x' , b = '5x'

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area=594=1/2*9x*12

594*2/12=9x

594/6=9x

99=9x

99/9=11=x

therefore, 4x=4*11=44cm

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5 0
1 year ago
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