<span><u><em>First way:</em></u>
The easiest and simplest way is to <u>count by 1</u> starting from 82 till you reach 512.
<u>This will go as follows:</u>
82, 83, 84, 85, ........... , 510, 511, 512
<u><em>Second way:</em></u>
We can note that the two given numbers are even numbers. This means that the two numbers are divisible by 2.
Therefore, we can <u>count by 2</u> starting from 82 till we reach 512.
<u>This will go as follows:</u>
82, 84, 86, 88, ................... , 508, 510, 512
<u><em>Third way:</em></u>
We can note that the units digit in both numbers is the same (the digit is 2). This means that we can count from 82 till 512 by <u>adding 10 each time</u>.
<u>This will go as follows:</u>
82, 92, 102, 112, ......................, 492, 502, 512
Hope this helps :)</span>
Answer:
1kg of salami cost $9.1
Step-by-step explanation:
Hailey paid $13 for 1 3/7 kg of sliced salami.
What was the cost per kilogram of salami?
Cost of 1 3/7 kg of sliced salami=$13
1 3/7 kg=10/7kg
Let x=1 kg of sliced salami
10/7 kg of x=$13
$13=10/7x
13=10/7*x
x=13 ÷ 10/7
=13×7/10
=91/10
=9.1
x=$9.1
Therefore, 1kg of salami cost $9.1
1/10 of 2000 is 200 pounds. so 200 pounds of cheese
i guess you mean 100 times more lettuce than beef so that would be 200,000 pounds of lettuce
200+200,000=200,200 final answer
Leanora is factoring in Amacher the factors of the thermometer are shown in the elevator 3+3 = 7 4+4 equalsTake away 100 and then +3 that gives you 6 billion in 2/3+6+4+3+8+9 that gives you a BCDEFGHIJK jelly jelly jelly diaper
Answer:
The standard deviation of the number of rushing yards for the running backs that season is 350.
Step-by-step explanation:
Consider the provided information.
The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.
Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.
Use the formula: 
Here z is 2.42 and μ is 790, substitute the respective values as shown.



Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.