Question

At present the sum of Monica's age and daughter's age is 44 years. . After 2 years Monica's age will be three times that if her daughter's age. find their present ages.

Answer 1

Answer:

Monica's age = 34 years

Her daughter's age = 10 years

Step-by-step explanation:

Let Monica's age = x

Let her daughter'sage = y

x + y = 44   -------> equ 1

After 2 years:

Monica's age = x + 2

Her daughter's age = y + 2

x + 2 = 3 * (y+2)

x + 2 = 3y + 6

      x = 3y + 6 -2

      x = 3y + 4

Put x value in equ 1:

    3y + 4 + y = 44

            4y = 44 - 4

             4y = 40

               y = 40/4

               y = 10

x = 44 -10

x = 34

Answer 2

Answer: Monica' present age =34 years

Daughter's present age = 10 years

Step-by-step explanation:

Let x =  Monica's present age.

y= Her daughter's present age .

As per given , we have

$x+y=44\\\\ y=44-x---(i)$

After two years,

Monica's age = x+2

Daughter's age = y+2

According to the question,

$3(y+2)=x+2---(ii)$

Use (i) in (ii), we get

$3(44-x+2)=x+2\\\\\Rightarrow\ 3(46-x)=x+2\\\\\Rightarrow\ 138-3x=x+2\\\\\Rightarrow\ x+3x=138-2\\\\\Rightarrow\ 4x=136\\\\\Rightarrow\ x=\dfrac{136}{4}\\\\\Rightarrow\ x=34$

Put value of x in (i) , we get

$y=44-34=10$

Hence, Monica' present age =34 years

Daughter's present age = 10 years