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zloy xaker [14]
1 year ago
11

According to (1.17), lei = 0 when regression model (1.1) is fitted to a set of n cases by the method of least squares. is it als

o true that l e:i = o? comment.
Mathematics
2 answers:
pychu [463]1 year ago
4 0

solution:

\sum ei =0

that is  

\sum (yi-yiˆ)=0

means,

\sumyi = \sum yiˆ

yi = \alpha +\beta xi+ei

yiˆ=\alphaˆ+\betaˆxi

so,

\sumei=0

hence proved

liberstina [14]1 year ago
3 0

Answer:

Properties of Fitted Regression Line

Step-by-step explanation:

We know that,

\sum{e_{i} } = 0

In turn we understand that

e_{i}= Y_{i}-Y'_{i}

The third property of Fitted Regression Line tells us that: The sum of the observed values Y_{i} equals the sum of the fitted values Y'_{i}, so:

\sum{Y_{i}} = \sum{Y'_{i}} (1)

We further understand that the values given for Y_{i}, is equivalent to:

Y_{i}= \beta_{0} + \beta_{1}X_{i}+\epsilon_{i} (2)

On the other hand for the definition of the value for the regression function of Y'_{i} is,

Y'_{i}= \beta_{0}+\beta_{1}X_{i} (3)

By replacing (3) and (2) in (1), we get that

\sum{ (\beta_{0} + \beta_{1}X_{i}+\epsilon_{i})} = \sum{(\beta_{0}+\beta_{1}X_{i})}

Since the sum is distributive

\sum \beta_{0} + \sum \beta_{1}X_{i}+\sum \epsilon_{i} = \sum\beta_{0}+ \sum \beta_{1}X_{i}

Equal values on opposite sides of an equation are canceled, we get that

\sum \epsilon_{i} = 0

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Answer:

6

Step-by-step explanation:

Factorize of the above numbers :

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66 = 2 • 3 • 11

84 = 22 • 3 • 7

Build a prime factors table

Number of times each prime factor

appears in the factorization of :

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Factor Number

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66 Number

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(min)

2 1 1 2 1

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Greatest Common Factor is :

6

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1 year ago
The diagram represents the factorization of a2+8a+12. A 2-column table with 2 rows. First column is labeled a with entries a squ
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Answer:

(A)6

Step-by-step explanation:

Given the quadratic expression: a^2+8a+12

We factorize:

a^2+8a+12=a^2+6a+2a+12\\=a(a+6)+2(a+6)\\=(a+2)(a+6)

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1 year ago
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The quality control manager at a light bulb factory needs to estimate the mean life of a batch (population) of light bulbs. We a
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Answer:

<em>a)95%  confidence intervals for the population mean of light bulbs in this batch</em>

(325.5 ,374.5)

b)

<em>The calculated value Z = 4 > 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The manufacturer has not right to take the average life of the light bulbs is 400 hours.</em>

Step-by-step explanation:

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

The tabulated value Z₀.₉₅ = 1.96

<em>95%  confidence intervals for the population mean of light bulbs in this batch</em>

<em></em>(x^{-} - Z_{\frac{\alpha }{2} } \frac{S.D}{\sqrt{n} } , x^{-} + Z_{\frac{\alpha }{2} }\frac{S.D}{\sqrt{n} } )<em></em>

<em></em>(350 - 1.96\frac{100}{\sqrt{64} } , 350 + 1.96\frac{100}{\sqrt{64} } )<em></em>

(350 -24.5, 350 +24.5)

(325.5 ,374.5)

b)

<u><em>Explanation</em></u>:-

Given mean of the Population μ = 400

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

<u><em>Null hypothesis</em></u> : H₀:The manufacturer has right to take the average life of the light bulbs is 400 hours.

μ = 400

<u><em>Alternative Hypothesis: H₁:</em></u> μ ≠400

<u><em>The test statistic </em></u>

Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }

Z = \frac{350 -400}{\frac{100}{\sqrt{64} } }

|Z| = |-4|

The tabulated value   Z₀.₉₅ = 1.96

The calculated value Z = 4 > 1.96 at 0.05 level of significance

Null hypothesis is rejected.

<u><em>Conclusion:</em></u>-

The manufacturer has not right to take the average life of the light bulbs is 400 hours.

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