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Archy [21]
1 year ago
12

In​ 2004, an art collector paid ​$ for a particular painting. The same painting sold for ​$ in 1950. Complete parts​ (a) through

​ (d). ​a) Find the exponential growth rate​ k, to three decimal​ places, and determine the exponential growth function​ V, for which​ V(t) is the​ painting's value, in​ dollars, t years after 1950.
Mathematics
1 answer:
azamat1 year ago
3 0

Answer:

The value of <em>k</em> is 0.149.

Step-by-step explanation:

The complete question is:

In 2004, an art collector paid $84,275,000 for a particular painting. The same painting sold for $27,000 in 1950. Complete part (a) through (d)? (a) Find exponential growth rate k, to three decimal places, and determine the exponential growth function V, for which V(t) is the painting’s value, in dollars, t years after 1950.

Solution:

The exponential growth function can be expressed as follows:

y=a\cdot e^{kt}

y = Final value after <em>t</em> years

a = initial value

It is provided that:

<em>y</em> = $84,275,000

<em>a</em> = $27,000

The value of <em>t</em> from 1950 to 2004 is, <em>t</em> = 54

Compute the value of <em>k</em> as follows:

y=a\cdot e^{kt}

84,275,000=27,000\times e^{54k}\\\\e^{54k}=\frac{84275000}{27000}\\\\54k=\ln (\frac{84275}{27})\\\\k=\frac{1}{54}\times \ln (\frac{84275}{27})\\\\k=0.149

Thus, the value of <em>k</em> is 0.149.

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A sample of 900 college freshmen were randomly selected for a national survey. Among the survey participants, 372 students were
Rufina [12.5K]

Answer:

a) ME=2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.0423

b) 0.413 - 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.371

Step-by-step explanation:

1) Data given and notation  

n=900 represent the random sample taken    

X=372 represent the students were pursuing liberal arts degrees

\hat p=\frac{372}{900}=0.413 estimated proportion of students were pursuing liberal arts degrees

\alpha=0.01 represent the significance level

z would represent the statistic (variable of interest)    

p_v represent the p value (variable of interest)    

p= population proportion of students were pursuing liberal arts degrees

2) Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

The margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

If we replace we have:

ME=2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.0423

And replacing into the confidence interval formula we got:

0.413 - 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.371

0.413 + 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.455

And the 99% confidence interval would be given (0.371;0.455).

We are confident (99%) that about 37.1% to 45.5% of students were pursuing liberal arts degrees.

7 0
2 years ago
Choose the product. -7p 3(4p 2 + 3p - 1)
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Answer:

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Step-by-step explanation:

-7p 3(4p 2+3p - 1)

3x4= 12p

3x3=9p

12+9= 21

21-7=14p

3x2=6

3x-3=-9

-9 +6= -3

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hope this helps :)

7 0
1 year ago
A lock has 5 buttons. The lock is opened by pushing two buttons simultaneously and then by pushing one button alone. How many co
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We first must calculate how many ways 2 oblects can be chosen from 5.

combinations = 5! / 2! * (5-2)!

combinations = 5*4 / 2

combinations = 10


There are 10 ways to choose the 2 buttons and 5 ways to choose the final butto so there are 10 * 5 = 50 different ways.


Source

1728.com/combinat.htm




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This item can be answered through the concept of fundamental principles of counting. In the first of the four digits, there are 10 possible digits. The same with all the other 3 places or digits of the code. That is,
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3 is incorrect because 14.7 + 3 = 17.7
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