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Artemon [7]
1 year ago
12

Which expression is equivalent to \left(3^{-6}\times 3^{3}\right)^{-1}\normalsize?(3 −6 ×3 3 ) −1 ? 3^{-19}3 −19 3^{18}3 18 3^{-

3}3 −3 3^{3}3 3
Mathematics
1 answer:
mars1129 [50]1 year ago
5 0

Answer:

27

Step-by-step explanation:

Given the expression

\left(3^{-6}\times 3^{3}\right)^{-1}\\

According to law of indices, this can be written as;

\left(3^{-6+3})^{-1}\\\\= (3^{-3})^{-1}\\\\= 3^{-3*-1}\\\\= 3^3\\\\= 27

Hence the required answer is 27

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23^0 is equal to _____. 0 1 1/23 23
Aliun [14]

Answer:

1

Step-by-step explanation:

Anything to the power is 0 is equal to 1.

5 0
2 years ago
Read 2 more answers
An account earns simple annual interest.<br><br> $925 at 2.3% for 2.4 years
aksik [14]

Answer:

$51.06

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

Well, 925x0.023=21.275

21.275x2.4=$51.06 in total

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

BTW, brainliest would be greatly appreciated, I only need one more before I advance, thanks!

5 0
2 years ago
Identify the segment bisector of JK
nordsb [41]

Answer:

A segment whose length is 9 units.

Step-by-step explanation:

A segment whose length is 9 units.

All we have is a bisection that divides equally segment JK in two parts. And M is the Midpoint what reassures us that JM=MK, so plugging in:

3x+15=8x+25

3x-8x=25-15

-5x=10

5x=-10

x=-2

JM=3(-2)+15 =9

MK=8(-2)+25=9

4 0
2 years ago
Fred buys a video game disk for $4 there was a discount of 20% what is the sales price please show work
polet [3.4K]

multiply the price by the discount then subtract the answer from the price

4 * 0.20 = 0.80

4-0.80 = 3.20

 sale price is $3.20

8 0
2 years ago
Which expression is equivalent to the expression below? StartFraction m + 3 Over m squared minus 16 EndFraction divided by Start
Kamila [148]

Option B: \frac{1}{(m-4)(m-3)} is the correct answer.

Explanation:

The given expression is \frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}

Simplifying the expression, we have,

\frac{m+3}{m^{2}-16}\times\frac{m+4}{m^2-9}

Factor the equations, m^{2}-16\right and m^{2}-9,we get,

m^{2}-16\right=m^{2}-4^{2}=(m+4)(m-4)

m^{2}-9=m^{2}-3^2=(m+3)(m-3)

Substituting these factored expressions in the above expression, we have,

\frac{m+3}{(m+4)(m-4)}\times\frac{m+4}{(m+3)(m-3)}

Cancelling the common terms m+3 and m+4 , we get,

\frac{1}{(m-4)(m-3)}

Thus, the expression equivalent to \frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )} is \frac{1}{(m-4)(m-3)}

Hence, Option B is the correct answer.

3 0
2 years ago
Read 2 more answers
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