123 lb * (0.4536 kg/lb) * 300mg/(kg · day)
= (123 * 0.4536 * 300) mg/day
= 16737.84 mg/day
16737.84 mg/day * 1g/(1000mg)
= 16.73784 g/day
Answer:
The amount of work required to remove all of the water by pumping it over the side = 3.12 × 10⁶ lbs.ft
Step-by-step explanation:
Work done in moving anything from point A to point B = Fx
For this setup,
If we take an elemental vertical height, dx, The volume would be A.dx
where A = Cross sectional Area = πr² = π(18)² = 1017.88 ft²
dV = 1017.88 dx
The elemental force on that part will be
dF = ρg dV
ρg = 63.8 lbs/ft³
dF = 63.8 × 1017.88 dx = 64940.5 dx
F = ∫dF = 64940.5 dx
W = Fx = (∫dF)x = ∫ 64940.5x dx = 64940.5 ∫ xdx
We'll be integrating from (11 - 6) ft to 11 ft because that's the total height it'll be pumped through
W = 64940.5 (x²/2)¹¹₅ = 64940.5((11² - 5²)/2) = 3.12 × 10⁶ lbs.ft
Answer:
c ≈ 26.4
Step-by-step explanation:
just use the pythagorean theorem
Answer:
StartFraction uppercase V squared minus v squared Over 2 s EndFraction = a
Step-by-step explanation:
