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1 year ago

$1.12 for 8.2 ounces? Unit Rate

1 answer:

4 0

That is around 13 or 14 cents. The specific answer is 13.65853659 cents, but you can either round up to 14 or round down to 13 (rounding up to 14 is the correct way to do it.)

First you divide 1.12 by 8.2 to get the unit rate because It takes $1.12 to buy 8.2 ounces. 1.12/8.2=13.65853659

You might be interested in

Write v as a linear combination of u1, u2, and u3, if possible. (If not possible, enter IMPOSSIBLE.) v = (7, −14, −3, −4), u1 =

AlexFokin [52]

Answer:

IMPOSSIBLE

Step-by-step explanation:

8 0

2 years ago

In 1998 the average income for middle class families in the US was $37,100 with a population standard deviation of $6362. We wan

sammy [17]

Answer:

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

The best answer would be:

A. Z test

Step-by-step explanation:

Data given and notation

$\bar X=36670$ represent the mean average

$\sigma=6362$ represent the population standard deviation for the sample

$n=1225$ sample size

$\mu_o =37100$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is equal or not to 37100, the system of hypothesis would be:

Null hypothesis: $\mu =37100$

Alternative hypothesis: $\mu \neq 37100$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

The best answer would be:

A. Z test

5 0

2 years ago

The area of a rectangle is 25/42 and its width is 5/6. What is the length? ASAP

Serhud [2]

Answer:

<h2> $length = \frac{25}{28}$ </h2>

Step-by-step explanation:

Let the length of the rectangle be l

Area of a rectangle = length × width

From the question

Area = 25/42

width = 5/6

Substitute the values into the above formula and solve for the length

That's

<h3> $length = \frac{area}{width}$ </h3>

So we have

<h3> $length = \frac{25}{42} \div \frac{4}{6} \\ = \frac{25}{42} \times \frac{6}{4} \\ = \frac{25}{7} \times \frac{1}{4}$ </h3>

We have the final answer as

Hope this helps you

8 0

1 year ago

A. [4 marks]

storchak [24]

The value of d is -2

Step-by-step explanation:

The nth term of the arithmetic sequence is $u_{n}=u_{1}+(n-1)d$ , where

$u_{1}$ is the first term
d is the common difference between each 2 consecutive terms

The nth term of the geometric sequence is $u_{n}=u_{1}r^{n-1}$ , where

$u_{1}$ is the first term
r is the common ratio between each two consecutive terms $r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}$

∵ $u_{1}$ of an arithmetic sequence is 1

∵ The common difference is d, where d ≠ 0

∵ $u_{2}$ , $u_{3}$ , $u_{6}$ are the first 3 terms of a geometric sequence

∵ $u_{2}$ = 1 + (2 - 1)d

∴ $u_{2}$ = 1 + d

∵ $u_{3}$ = 1 + (3 - 1)d

∴ $u_{2}$ = 1 + 2d

∵ $u_{6}$ = 1 + (6 - 1)d

∴ $u_{2}$ = 1 + 5d

∴ The first 3 terms of the geometric sequence are (1 + d) , (1 + 2d) ,

(1 + 5d)

∵ The common ratio in the geometric sequence is $r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}$

∴ $r=\frac{1+2d}{1+d}=\frac{1+5d}{1+2d}$

- Use cross multiplication with the equal fractions

∵ $\frac{1+2d}{1+d}=\frac{1+5d}{1+2d}$

∴ (1 + 2d)(1 + 2d) = (1 + d)(1 + 5d)

∴ 1 + 2d + 2d + 4d² = 1 + 5d + d + 5d²

- Add like terms in each side

∴ 1 + 4d + 4d² = 1 + 6d + 5d²

- Subtract 1 from both sides

∴ 4d + 4d² = 6d + 5d²

- Subtract 4d from both sides

∴ 4d² = 2d + 5d²

- Subtract 4d² from each side

∴ 0 = 2d + d²

- Take d as a common factor

∴ 0 = d(2 + d)

- Equate each factor by 0

∴ d = 0 but we will reject it because d ≠ 0

∴ 2 + d = 0

- Subtract 2 from both sides

∴ d = -2

The value of d is -2

Learn more:

You can learn more about the sequence in brainly.com/question/1522572

#LearnwithBrainly

7 0

2 years ago

Find the median for the given set of data 0.6 , 1.1, 0.87, 2, 0.87, 1.23

Bezzdna [24]

To find the median, place the numbers in order from least to greatest then find the number in the middle

0.6, 0.87, (0.87, 1.1), 1.23, 2

0.87 and 1.1 are in the center.

Add 0.87 to 1.1 then divide it by 2

0.87 + 1.1 = 1.97

Half of 1.97 is 0.985

Hope this helps

4 0

2 years ago

Read 2 more answers