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ValentinkaMS [17]
2 years ago
14

The final velocity, V, of an object under constant acceleration can be found using the formula uppercase V squared = v squared +

2 a s, where v is the initial velocity (in meters per second), a is acceleration (in meters per second), and s is the distance (in meters). What is the formula solved for a?
uppercase V squared minus v squared minus 2 x = a
uppercase V squared minus v squared + 2 s = a
StartFraction uppercase V squared minus v squared Over 2 s EndFraction = a
StartFraction uppercase V squared plus v squared Over 2 s EndFraction = a
Mathematics
2 answers:
Anon25 [30]2 years ago
8 0

Answer:

StartFraction uppercase V squared minus v squared Over 2 s EndFraction = a

Step-by-step explanation:

Diano4ka-milaya [45]2 years ago
6 0

Answer:

C

Step-by-step explanation:

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On a coordinate plane, line P Q goes through (negative 6, 4) and (4, negative 4). Point R On a coordinate plane, a line goes thr
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Answer:

x + 2y = 8.

Step-by-step explanation:

Line goes through (-4, 0) and (4, -4).

The slope is (-4 - 0) / (4 - -4) = -4 / (4 + 4) = -4 / 8 = -1/2.

Since we are looking for the equation of the line parallel to that line, the slope will be the same.

We have an equation of y = -1/2x + b. We have a point at (2, 3). We can then say that y = 3 when x = 2.

3 = (-1/2) * 2 + b

b - 1 = 3

b = 4.

So, we have y = -1/2x + 4.

1/2x + y = 4

x + 2y = 8.

Hope this helps!

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What is the final amount if 784 is decreased by 1% followed by a 4% increase?
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Answer:

The final amount  if 784 is decreased by 1% followed by a 4% increase is 807.52.

Step-by-step explanation:

General Formula

<em>A way to solve this problem is as follows</em>:

The general formula for this is taking into account that:

\\ percent\;change = \frac{change}{starting\;point}

The <em>starting point</em> is number 784.

The most important key is the solution for this answer is that:

\\ change = starting\;point - x

Where <em>x</em> is a number that we need to find. Then

\\ percent\;change = \frac{starting\;point - x}{starting\;point} [1]

Is 784 increased or decreased after all?

We also need to evaluate the following: if a quantity decreases a percentage, and then increases in another percentage, what is the final percentage? In this case, we have first that 784 decreases by 1% and then increases by 4%. As a result 784 will +4% - 1% = +3%, that is, 784 will increase in 3%.

Finding the result

If 784 increases by 3%, we have:

\\ 3\% = \frac{784 - x}{784}

Which is equal to

\\ 0.03 = \frac{784 - x}{784}

Solving for <em>x</em>, we first multiply by 784 to both sides of the previous formula:

\\ 0.03 * 784 = \frac{784 - x}{784}*784

\\ 0.03 * 784 = (784 - x)*\frac{784}{784}

\\ 0.03 * 784 = (784 - x)*1

\\ 0.03 * 784 = (784 - x)

Remember that if we add, subtract, multiply, divide... to both sides of the equation, we do not "alter" this equation.

Subtracting 784 to both sides:

\\ (0.03 * 784) - 784 = (784 - 784 - x)

\\ (0.03 * 784) - 784 = (0 - x)

\\ (0.03 * 784) - 784 = - x

\\ 23.52 - 784 = - x

\\ -760.48 = - x

Multiplying by -1 to both sides:

\\ -1 * (-760.48) = -1 * (-x)

We have to remember that:

\\ +*+ = +; - * - = +; - * + = -; + * - = -

\\ 760.48 = x

Then

\\ x = 760.48

Therefore, using formula [1], an increase of 3% is

\\ 3\% = \frac{784 - 760.48}{784}

\\ change = 784 - 760.48

\\ change = 23.52

Since an increase of 3% is 23.52, we have to add this to the starting point 784, and finally the amount is 784 + 23.52 = 807.52.

As a result, the final amount if 784 is decreased by 1% followed by a 4% increase is 807.52.  

In a more <em>terse way</em> of solving this problem, we can say that:

Increase of 4% = 784 * 0.04 = 31.36.

Decrease of 1% = 784 * 0.01 = 7.84.

Difference = 31.36 - 7.84 = 23.52.

Then, we need to add this value to 784, and 784 + 23.52 = 807.52 (the same result).

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Thus, we just need to find when h = 0 so that we find when it hits the ground.

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So, t = 6 or -2, but t ≠ -2, since time cannot be negative in this instance.

Hence, at 6 seconds, the ball will strike the ground.
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