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ValentinkaMS [17]
2 years ago
14

The final velocity, V, of an object under constant acceleration can be found using the formula uppercase V squared = v squared +

2 a s, where v is the initial velocity (in meters per second), a is acceleration (in meters per second), and s is the distance (in meters). What is the formula solved for a?
uppercase V squared minus v squared minus 2 x = a
uppercase V squared minus v squared + 2 s = a
StartFraction uppercase V squared minus v squared Over 2 s EndFraction = a
StartFraction uppercase V squared plus v squared Over 2 s EndFraction = a
Mathematics
2 answers:
Anon25 [30]2 years ago
8 0

Answer:

StartFraction uppercase V squared minus v squared Over 2 s EndFraction = a

Step-by-step explanation:

Diano4ka-milaya [45]2 years ago
6 0

Answer:

C

Step-by-step explanation:

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A garden supply store sells two types of lawn mowers. The smaller mower costs $249.99 and the larger mower costs $329.99. If 30
Annette [7]

19 small mowers and 11 large mowers are sold

<em><u>Solution:</u></em>

Let "a" be the number of small mowers sold

Let "b" be the number of large mowers sold

Cost of each small mower = $ 249.99

Cost of each large mower = $ 329.99

<em><u>30 total mowers were sold</u></em>

Therefore,

a + b = 30

a = 30 - b ------------- eqn 1

<em><u>The total sales for a given year was $8379.70</u></em>

<em><u>Thus we frame a equation as:</u></em>

number of small mowers sold x Cost of each small mower + number of large mowers sold x Cost of each large mower = 8379.70

a \times 249.99 + b \times 329.99 = 8379.70

249.99a + 329.99b = 8379.70 ---------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 1 in eqn 2</u></em>

249.99(30 - b) + 329.99b = 8379.70

7499.7 - 249.99b + 329.99b = 8379.70

80b = 8379.70 - 7499.7

80b = 880

Divide both sides by 80

b = 11

<em><u>Substitute b = 11 in eqn 1</u></em>

a = 30 - 11

a = 19

Thus 19 small mowers and 11 large mowers are sold

8 0
2 years ago
The graphs shown are of the form y = ax2. Which graph has the smallest value for a?
Talja [164]
y= x^{2} is a parabola (looks like the letter U).

The letter a represents the coefficient of x^{2} and it controls two things (1) how wide or narrow the parabola is and (2) whether it is concave up (like a U) or concave down (like an up-side-down).

The absolute value of a (the number without the sign) controls how wide or narrow it is. If the absolute value is a fraction less than 1 the graph gets wider. The smaller the absolute value of the fraction the wider the graph gets.

If the absolute value of a is greater than 1 the graph gets narrower (it gets skinnier). The bigger the absolute value the narrower the graph.

So, if all the graphs look like a U (concave up) then the one with the smallest a is the one that is the widest.

The a also controls whether the graph is concave up or concave down. If a is negative

If a is negative the graph is concave down so any graph that is concave down has a smaller value of a than any graph that is concave up. However, if the graph is concave down the one with the smallest a would be the most narrow one.

So to find the one with the smallest a...
If they are all concave up (like a U) pick the widest one
and
If they are not all concave up pick the narrowest one that is concave down (looks like an upside down U)
3 0
2 years ago
A sample of 75 concrete blocks had a mean mass of 38.3 kg with a standard deviation of 0.6 kg.
Scilla [17]
The answer will be a
8 0
2 years ago
Given log Subscript 4 Baseline 3 almost-equals 0.792 and log Subscript 4 Baseline 21 almost-equals 2.196, what is log Subscript
defon

Answer:

Step-by-step explanation:

The following is the logarithm quotient rule:

log_{c}{a / b} = log_{c}{a} - log_{c}{b}

Plugging in the values we have above gives us the following:

log_{4}{21 / 3} = log_{4}{21} - log_{4}{3}

log_{4}{7} = 2.196 - 0.792

log_{4}{7} = 1.404

6 0
2 years ago
Read 2 more answers
Suppose that a random sample of size 100 is to be selected from a population with mean 50 and standard deviation 8. What is the
maksim [4K]

Answer:

0.159

Step-by-step explanation:

Given that:

Sample size (n) = 100

Population mean(pm) = 50

Standard deviation (s) = 8

Probability that Sample mean (m) will be greater Than 50.8

Using the relation :

(sample mean - population mean) / (standard deviation /sqrt(n))

P(m > 50.8)

Z = (50.8 - 50) / (8/ sqrt(100))

Z = 0.8 / (8/ 10)

Z = 0.8 / 0.8

Z = 1

P(Z > 1) = 0.15866 ( Z probability calculator)

Hence,

P(Z > 1) = 0.159 ( 3 decimal places)

7 0
1 year ago
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