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Reptile [31]
2 years ago
11

Suppose that a random sample of size 100 is to be selected from a population with mean 50 and standard deviation 8. What is the

probability that a sample mean will be greater than 50.8? Round your answer to three decimal places.
Mathematics
1 answer:
maksim [4K]2 years ago
7 0

Answer:

0.159

Step-by-step explanation:

Given that:

Sample size (n) = 100

Population mean(pm) = 50

Standard deviation (s) = 8

Probability that Sample mean (m) will be greater Than 50.8

Using the relation :

(sample mean - population mean) / (standard deviation /sqrt(n))

P(m > 50.8)

Z = (50.8 - 50) / (8/ sqrt(100))

Z = 0.8 / (8/ 10)

Z = 0.8 / 0.8

Z = 1

P(Z > 1) = 0.15866 ( Z probability calculator)

Hence,

P(Z > 1) = 0.159 ( 3 decimal places)

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The square of a number decreased by 3 times the number 28 find all possible values for the number
stealth61 [152]

Question:

The square of a number decreased by 3 times the number is 28 find all possible values for the number  

Answer:

The possible values of number are 7 and -4

Solution:

Given that the square of a number decreased by 3 times the number is 28

To find: all possible values of number

Let "a" be the unknown number

From given information,

square of a number decreased by 3 times the number = 28

a^2 - 3a = 28

a^2 - 3a - 28 = 0

Let us solve the above quadratic equation

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Using the above formula,

\text { For } a^{2}-3 a-28=0 \text { we have } a=1, b=-3, c=-28

\begin{aligned}&a=\frac{-(-3) \pm \sqrt{(-3)^{2}-4(1)(-28)}}{2 \times 1}\\\\&a=\frac{3 \pm \sqrt{9+112}}{2}\\\\&a=\frac{3 \pm \sqrt{121}}{2}=\frac{3 \pm 11}{2}\\\\&a=\frac{3+11}{2} \text { or } a=\frac{3-11}{2}\\\\&a=7 \text { or } a=-4\end{aligned}

Thus the possible values of number are 7 and -4

5 0
2 years ago
A political polling agency wants to take a random sample of registered voters and ask whether or not they will vote for a certai
bonufazy [111]

Answer:

C. Different sample proportions would result each time, but for either sample size, they would be centered (have their mean) at the true population proportion.

Step-by-step explanation:

From the given information;

A political polling agency wants to take a random sample of registered voters and ask whether or not they will vote for a certain candidate.

A random sample is usually an outcome of any experiment that cannot be predicted before the result.

SO;

One plan is to select 400 voters, another plan is to select 1,600 voters

If the study were conducted repeatedly (selecting different samples of people each time);

Different sample proportions would result each time, but for either sample size, they would be centered (have their mean) at the true population proportion.  This is because a sample proportion deals with random experiments that cannot be predicted in advance and they  are  quite known to be centered about the population proportion.

5 0
2 years ago
Comparing Two Linear Functions Use the graph and table to answer the questions. Which vehicle loses the most value each year? Ca
MakcuM [25]

Answer:

Use the graph and table to answer the questions.

Which vehicle loses the most value each year?

Car

Which vehicle will lose all of its value first?

Car

If the truck’s rate of depreciation changes to a decrease of $1,650 each year, which vehicle will lose all of its value first?

Truck

Step-by-step explanation:

4 0
2 years ago
Find the interest due to the bank on a loan of $1000 at 7.5% for 280 days
Lera25 [3.4K]

Answer:

The interest is \$57.53

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=280/365\ years\\ P=\$1.000\\r=0.075

substitute in the formula above

I=\$1.000(0.075*280/365)

I=\$57.53

7 0
2 years ago
Ryan invested some money in his bank he agreed a simple interest rate of 4% per annum for a 2 years At the end of the 2- years p
sdas [7]

\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$P\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &2 \end{cases} \\\\\\ I=P(0.04)(2)\implies I=0.08P\implies \stackrel{\textit{converting it to percentage}~\hfill }{0.08\cdot 100\implies 8\%\textit{ of original }P}

4 0
2 years ago
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